一个获取远端文件的函数(Linux和Windows均适用)_PHP
为了获取远端文件,编写了下面的一个小函数,基本各方面都考虑了,大家看看吧:
function getpic($url,$dir,$name){
//获取url文件,然后存放到dir目录中,以name为文件名。
//如果缺省文件名,则保留原文件名。
$tmp=split("/",$url);
$fname=$tmp[count($tmp)-1];//获取文件名
if(empty($name)) {
$name=$fname;//设定好文件名
}else{//判断是否更改了文件的扩展名,如果更改的话,则改为文件本身的扩展名。
$tmp1=split("\.",$fname);
$tmp2=split("\.",$name);
if(strcmp($tmp1[1],$tmp2[1])!=0) $name=$tmp2[0].".".$tmp1[1];
}
if(strstr($dir,"\\")){//说明是Windows环境下的目录
if(substr($dir,-2)=="\\") $file=$dir.$name;else $file=$dir."\\".$name;
}else{
if(substr($dir,"/")){//说明是Linux环境下的目录
if(substr($dir,-1)=="/") $file=$dir.$name;else $file=$dir."/".$fname;
}
else{ //给了一个非法的目录,函数退出
echo "error directory!";
return ;
}
}
if(!(file_exists("$dir") && is_dir("$dir"))) {//如果目录不存在,则创建目录
mkdir($dir,0777);
}
if(file_exists($file)) return;//如果文件存在,则放弃操作
$fpo=fopen($file,"wb");
if(!$fpo){
echo "Sorry,create file:$file failure!Check your right!";
return ;
}
$num=0;
do{
$num++;
$fpi=fopen($url,"r");
if(!$fpi) echo "open remote file falure...Retry!\r\n";
}while(!$fpi && $num
if(!fpi){
echo "The network is buzy or Bad URL!";
return ;
}else echo "Open file OK!Now transfer....";
while(!feof($fpi)){
$cont=fread($fpi,128);
fwrite($fpo,$cont,128);
}
fclose($fpi);
fclose($fpo);
echo "Success!";
}

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