How to design a high-performance MySQL table structure to implement the food recommendation function?
As people’s demand for food becomes higher and higher, the application of recommendation systems in the field of food is gradually increasing. Designing a high-performance MySQL table structure to implement the food recommendation function will play an important role in improving user experience and platform development. This article will introduce how to design such a table structure and provide specific code examples.
1. Requirements Analysis
Before designing a high-performance food recommendation system, it is first necessary to clarify the system requirements. Generally speaking, a food recommendation system needs to meet the following requirements:
2. Table design
Based on the above demand analysis, we can design the following table structures to support the function of the food recommendation system:
CREATE TABLE user
(
user_id
INT PRIMARY KEY AUTO_INCREMENT,
username
VARCHAR(100) NOT NULL ,
gender
ENUM('male', 'female') NOT NULL,
age
INT NOT NULL
);
CREATE TABLE food
(
food_id
INT PRIMARY KEY AUTO_INCREMENT,
food_name
VARCHAR(100) NOT NULL ,
food_type
VARCHAR(100) NOT NULL
);
CREATE TABLE user_food_rating
(
user_id
INT NOT NULL,
food_id
INT NOT NULL,
rating
FLOAT NOT NULL,
PRIMARY KEY (user_id
, food_id
),
FOREIGN KEY (user_id
) REFERENCES user
(user_id
),
FOREIGN KEY (food_id
) REFERENCES food
(food_id
)
);
CREATE TABLE user_food_preference
(
user_id
INT NOT NULL,
food_id
INT NOT NULL,
preference
FLOAT NOT NULL,
PRIMARY KEY (user_id
, food_id
),
FOREIGN KEY (user_id
) REFERENCES user
(user_id
),
FOREIGN KEY (food_id
) REFERENCES food
(food_id
)
);
CREATE TABLE food_similarity
(
food_id1
INT NOT NULL,
food_id2
INT NOT NULL,
similarity
FLOAT NOT NULL,
PRIMARY KEY (food_id1
, food_id2
),
FOREIGN KEY (food_id1
) REFERENCES food
(food_id
),
FOREIGN KEY (food_id2
) REFERENCES food
(food_id
)
);
3. Code example
SELECT f.food_name, f.food_type
FROM food f
INNER JOIN (
SELECT food_id, SUM(similarity * preference) AS score
FROM user_food_preference ufp
INNER JOIN food_similarity fs ON ufp.food_id = fs.food_id1
WHERE ufp.user_id = 1
GROUP BY food_id
) AS t ON f.food_id = t.food_id
ORDER BY score DESC
LIMIT 10;
INSERT INTO user_food_rating (user_id, food_id, rating)
VALUES (1, 1001, 4.5)
ON DUPLICATE KEY UPDATE rating = 4.5;
The above code examples are for reference only , which may need to be modified according to specific circumstances in actual applications.
In summary, through reasonable MySQL table structure design and optimization, a high-performance food recommendation system can be realized. At the same time, combined with real-time updated strategies and accurate recommendation algorithms, it can provide users with food recommendations that best suit their tastes. Of course, in practical applications, other factors need to be considered, such as cache, search engines, data sharding, etc., to further improve the performance and accuracy of the system.
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