How to write the following Java program

How to write the following java program

3. Write a class to demonstrate defining a variable of type int, assigning it a value, and then printing it on the console

public class two{

public static void main(String args[]){

int a = 123;

System.out.println(a);

}

}

5. Output the following form

public class four {

public static void main(String[] args){

char [][] a =new char[5][5];

int i, j;

for(i=0;ifor(j=0;jif(j>=i)

a[i][j]='*';

else

a[i][j]=' ';

}

for(i=0;ifor(j=0;jSystem.out.print(a[i][j]);

System.out.println();

}

}

}

2. Write a class to test and demonstrate the meaning of the and - operator.

public class first{

public static void main(String args[]){

int a = 5;

System.out.println("a : " (a ));

System.out.println("a-- : " (a--));

System.out.println(＂ a : ＂ ( a));

System.out.println("--a : " (--a));

}

}

4. Program to compare the sizes of 23 and 32, and output the result.

public class first{

public static void main(String args[]){

int a = 23;

int b = 32;

if(aSystem.out.println(a "}else{

System.out.println(a ＂>＂ b);

}

}

}

Ask a question about php value

Look at this sentence in your programselect[] is data in the form of an array. When you use echo to output an array, the array is displayed to tell you that the variable is an array.

Change your program to this if($_POST['submit']){echo ＂Your choice is
＂; foreach ($_POST['select'] as $bookname) { echo ＂$bookname
";}} Use foreach to traverse the array output.

There is no line break in the above, which looks more laborious. hehe

Repost

if($_POST['submit']) { echo "Your choice is:
";

foreach ($_POST['select'] as $bookname) { echo ＂$bookname
＂; }

}

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