In-depth analysis of the difference between value passing and reference passing in Java
In Java programming, we often encounter the situation of passing parameters, and the parameter passing There are two ways: passing by value and passing by reference. These two delivery methods have different characteristics and application scenarios in Java.
Pass-by-Value refers to passing the value of the actual parameter to the formal parameter when the function is called. Modifications to the formal parameters within the function will not affect the value of the actual parameter. Pass-by-Reference means that when a function is called, the reference of the actual parameter is passed to the formal parameter. Modifications to the formal parameters within the function will affect the actual parameters.
In order to better understand the difference between value passing and reference passing, let's look at a simple sample code:
public class PassByValueDemo { public static void main(String[] args) { int num1 = 10; int num2 = 20; System.out.println("交换前:num1=" + num1 + ", num2=" + num2); swap(num1, num2); System.out.println("交换后:num1=" + num1 + ", num2=" + num2); Person person1 = new Person("Tom"); Person person2 = new Person("Jerry"); System.out.println("交换前:person1=" + person1 + ", person2=" + person2); swap(person1, person2); System.out.println("交换后:person1=" + person1 + ", person2=" + person2); } public static void swap(int a, int b) { int temp = a; a = b; b = temp; } public static void swap(Person p1, Person p2) { Person temp = p1; p1 = p2; p2 = temp; } } class Person { private String name; public Person(String name) { this.name = name; } @Override public String toString() { return name; } }
In the above code, we pass the swap
method To exchange two numbers and the values of two Person
objects. In the case of value passing, we expect the swap
method to be able to exchange numbers and values of Person
objects. However, after running the code, we will find that only the values of the numbers have been exchanged, and the value of the Person
object has not changed.
This is because value transfer in Java copies the value of the actual parameter to the formal parameter, and modifies the formal parameter inside the function without affecting the original actual parameter. Therefore, in the swap(int a, int b)
method, the values of a
and b
are exchanged without affecting the values of num1
and The value of num2
.
For the exchange in the swap(Person p1, Person p2)
method, we expect to be able to exchange the values of person1
and person2
. However, since reference passing in Java is to pass the reference of the actual parameter to the formal parameter, the formal parameter and the actual parameter point to the same object. During the exchange process, we only exchanged the references of the formal parameters p1
and p2
, but did not modify the actual parameters person1
and person2
points to the object, so the exchange does not take effect.
The Person
object can be correctly exchanged with the following code:
public static void swap(Person p1, Person p2) { String temp = p1.getName(); p1.setName(p2.getName()); p2.setName(temp); }
In the above code, by calling getName()
and setName ()
method to obtain and modify the attribute values of the Person
object to achieve correct object exchange.
To sum up, value passing and reference passing are two different parameter passing methods in Java. Passing by value does not modify the value of the actual parameter, while passing by reference modifies the object pointed to by the actual parameter. Understanding and correctly using these two delivery methods is very important for Java programming.
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