mysql 常用数据库语句 小练习_MySQL
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闲来无事,上班时找了个练习来写,联系题目是针对sql server 2000的以下为mysql
一 单词解释(2分/个) 34分
Data 数据 Database 数据库 RDBMS 关系数据库管理系统 GRANT 授权
REVOKE 取消权限 DENY 拒绝权限 DECLARE 定义变量 PROCEDURE存储过程
事务 Transaction 触发器 TRIGGER 继续 continue 唯一 unqiue
主键 primary key 标识列 identity 外键 foreign key 检查 check
约束 constraint
--------------------------------------------------------------------
1) 创建一张学生表,包含以下信息,学号,姓名,年龄,性别,家庭住址,联系电话
create table student
(
学号 int,
姓名 varchar(10),
年龄 int,
性别 varchar(4),
家庭住址 varchar(50),
联系电话 varchar(11)
);
--------------------------------------------------------------------
2) 修改学生表的结构,添加一列信息,学历
alter table student add column 学历 varchar(6);
--------------------------------------------------------------------
3) 修改学生表的结构,删除一列信息,家庭住址
alter table student drop column 家庭住址;//注意此处用drop而非delete
--------------------------------------------------------------------
4) 向学生表添加如下信息:
学号 姓名年龄性别联系电话学历
1A22男123456小学
2B21男119中学
3C23男110高中
4D18女114大学
insert into student (学号,姓名,年龄,性别,联系电话,学历) values(1,"A",22,"男","123456","小学");
insert into student (学号,姓名,年龄,性别,联系电话,学历) values(1,"B",21,"男","119","中学");
insert into student (学号,姓名,年龄,性别,联系电话,学历) values(1,"C",23,"男","123456","高中");
insert into student (学号,姓名,年龄,性别,联系电话,学历) values(1,"D",23,"女","114","大学");
--------------------------------------------------------------------
5) 修改学生表的数据,将电话号码以11开头的学员的学历改为“大专”
update student set 学历="大专" where 联系电话 like "11%";
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6) 删除学生表的数据,姓名以C开头,性别为‘男'的记录删除
delete from student where 姓名 like "C" and 性别="男";
--------------------------------------------------------------------
7) 查询学生表的数据,将所有年龄小于22岁的,学历为“大专”的,学生的姓名和学号示出来
select 姓名,学号 from student where 年龄--------------------------------------------------------------------
8) 查询学生表的数据,查询所有信息,列出前25%的记录
select top 25 percent * from student ; ????
select * from student limit 25%;????
这条有问题,在sql 2000中应该是select top 25 percent * from student ;
--------------------------------------------------------------------
9) 查询出所有学生的姓名,性别,年龄降序排列
select 姓名,性别,年龄 from student order by 年龄 desc;
--------------------------------------------------------------------
10) 按照性别分组查询所有的平均年龄
select avg(年龄) as 平均年龄 from student group by 性别;
select avg(年龄) from student group by 性别;
select avg(年龄) 平均年龄 from student group by 性别;
--------------------------------------------------------------------
3) 说出以下聚合数的含义:avg ,sum ,max ,min , count ,count(*)
AVG:求平均值
SUM:求和
MAX:求最大值
MIN:求最小值
COUNT(*):返回所有行数
COUNT返回满足指定条件的记录值bitsCN.com

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