Use time.Parse to parse the different times before and after

Question content

I need to receive a time as a string, parse it, and then render it as a string again:

package main

import ("fmt"; "time")

func main() {
  const timelayout = "mon, jan 2, 2006 15:04 pm"
  sourcetime :=      "mon, apr 7, 2025 7:36 pm"
  mytime, err := time.parse(timelayout, sourcetime)
  if err != nil { panic(err) }
  fmt.printf("\t\tsourcetime = \"%s\"\n mytime.format(timelayout) = \"%s\"\n",
    sourcetime, mytime.format(timelayout))
}

This is my expected output:

sourcetime = "mon, apr 7, 2025 7:36 pm"
 mytime.format(timelayout) = "mon, apr 7, 2025 7:36 pm"

But I received this strange output:

sourceTime = "Mon, Apr 7, 2025 7:36 PM"
 myTime.Format(timeLayout) = "Mon, Apr 7, 2025 19:36 PM"

I didn't change something in the variable, so why am I receiving different results for the same layout? I shouldn't change this time layout. But again I need to receive the source string as result.

Correct answer

Your time layout uses the 24 hour clock (e.g. 15:04 instead of 3:04), so when you format it you will Get 19 instead of 7. If you want a 12 hour format, your time layout would be "Monday, January 2, 2006 3:04 PM"

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