


Convert Excel file data to JSON string in Go without any struct definition
I am new to go language. I have a requirement where an application will read an excel file and convert it into a json string without relying on any defined structure. I explored a few libraries where either this structure definition is required or at least there must be excel column headers. For example,
github.com/xuri/excelize github.com/onkarvhanumante/Excel2JsonTree github.com/FerdinaKusumah/excel2json
However, I can't find anywhere that can handle raw excel data and convert it to json.
Please give me some guidance, thank you!
Correct answer
If you can treat all values as strings, then you can do it as shown in the code snippet below. The script reads all worksheets (tabs) and creates json files in two formats (with and without headers).
package main import ( "encoding/json" "fmt" "os" "github.com/xuri/excelize/v2" ) func main() { f, err := excelize.OpenFile("test.xlsx") if err != nil { fmt.Println(err) return } defer func() { if err := f.Close(); err != nil { fmt.Println(err) } }() // could have multiple sheets sheets := f.GetSheetList() for _, sheetName := range sheets { d, err := f.GetRows(sheetName) if err != nil { fmt.Println("error reading sheet", sheetName, ":", err) return } saveAsJSON(d, sheetName+".json") saveAsJSONWithHeaders(d, sheetName+"_with_headers.json") } } func saveAsJSONWithHeaders(rows [][]string, filename string) error { data := make([]map[string]string, len(rows)-1) headers := rows[0] // excluding header row for i, row := range rows[1:] { data[i] = make(map[string]string) for j, cellValue := range row { data[i][headers[j]] = cellValue } } return saveAsJSON(data, filename) } func saveAsJSON(data interface{}, filename string) error { file, err := os.Create(filename) if err != nil { return err } defer file.Close() encoder := json.NewEncoder(file) if err := encoder.Encode(data); err != nil { return err } return nil }
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