Copy bytes into struct fields using reflection

php editor strawberry introduction: In programming, sometimes we need to copy byte data into the fields of the structure. This process can be achieved by using reflection. Reflection is a powerful tool for inspecting and manipulating code structures at runtime. Through reflection, we can obtain the field information of the structure and copy the byte data into the structure according to the type and order of the fields to realize data conversion and assignment. This approach can bring us convenience and flexibility, allowing us to process byte data more efficiently.

Question content

How to iterate slices of bytes and assign them to fields of a structure?

type s struct {
  f1 []byte
  f2 []byte
  f3 []byte
}

func S s {
  x := s{}
  x.f1 = make([]byte, 4)
  x.f1 = make([]byte, 2)
  x.f1 = make([]byte, 2)
  return x
}

func main() {
  data := []byte{83, 117, 110, 83, 0, 1, 0, 65}

  Z := S()
  //pesudo code from here
  i:= 0
  for field in Z {
    field = data[i:len(field)]
    i += len(field)
  }

expect:

• f1 = [83,117,110,83]
• f2 = [0,1]
• f3 = [0,65]

I've done this before in c/c but I don't know how to do it in go. I need a generic allocation function because I will have several different structures, some of which may not exist in the stream.

Ideally I would like to pass the initialized struct and my code will iteratively populate their struct fields.

Workaround

Use the reflection code in the binary/encoding package.

Step 1: Declare the field as an array instead of a slice.

type s struct {
  f1 [4]byte
  f2 [2]byte
  f3 [2]byte
}

Step 2: Use binary.read to decode the data into a structure

var s s
data := []byte{83, 117, 110, 83, 0, 1, 0, 65}
err := binary.read(bytes.newreader(data), binary.littleendian, &s)
if err != nil {
    log.fatal(err)
}

Step 3: Finished!

fmt.Print(s) // prints {[83 117 110 83] [0 1] [0 65]}

https://www.php.cn/link/42ae1544956fbe6e09242e6cd752444c

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