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How to properly use the AnonFiles API to publish files?

王林
Release: 2024-02-09 09:12:29
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如何正确使用AnonFiles API发布文件?

php小编苹果为您带来关于如何正确使用AnonFiles API发布文件的指南。AnonFiles API是一个强大的工具,可以帮助您快速、安全地上传和分享文件。本指南将为您提供详细的步骤和示例,帮助您轻松掌握API的使用方法。无论您是开发者还是普通用户,都能从本指南中获得实用的技巧和建议,让您的文件分享体验更加顺畅和高效。让我们一起来探索AnonFiles API的魅力吧!

问题内容

我正在尝试创建一个函数,使用 anonfiles api 在 anonfiles.com 网站上托管您的文件。即使我正确使用了 api,它总是返回 nil。 响应缺少消息

func host(file string) {
    fileBytes, err := ioutil.ReadFile(file)
    if err != nil {
        fmt.Println("\033[1;31mCommand > Host: Could not read file,", err, "\033[0m")
        return
    }

    url := "https://api.anonfiles.com/upload"

    request, err := http.NewRequest("POST", url, bytes.NewBuffer(fileBytes))
    if err != nil {
        fmt.Println("\033[1;31mCommand > Host: Could not post request,", err, "\033[0m")
        return
    }

    request.Header.Set("Content-Type", "application/octet-stream")

    client := &http.Client{}
    response, err := client.Do(request)
    if err != nil {
        fmt.Println("\033[1;31mCommand > Host: Could not send request,", err, "\033[0m")
        return
    }
    defer response.Body.Close()

    body, err := ioutil.ReadAll(response.Body)
    if err != nil {
        fmt.Println("\033[1;31mCommand > Host: Could not read response,", err, "\033[0m")
        return
    }

    var result map[string]interface{}
    err = json.Unmarshal(body, &result)
    if err != nil {
        fmt.Println("\033[1;31mCommand > Host: Could not parse response,", err, "\033[0m")
        return
    }

    if response.StatusCode == 200 {
        if result["url"] == nil {
            fmt.Println("\033[1;31mCommand > Host: Response is missing URL\033[0m")
            return
        }
        fmt.Println("File hosted successfully:", result["url"].(string))
    } else {
        if result["message"] == nil {
            fmt.Println("\033[1;31mCommand > Host: Response is missing message\033[0m")
            return
        }
        fmt.Println("\033[1;31mCommand > Host:\033[0m", result["message"].(string))
    }
}
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解决方法

我想花点时间将这些评论扩展为答案。

首先,正如我们已经讨论过的,您没有使用正确的 api 来上传文件。如果我们修改您的代码以显示完整的响应正文,如下所示:

client := &http.client{}
response, err := client.do(request)
if err != nil {
  fmt.println("\033[1;31mcommand > host: could not send request,", err, "\033[0m")
  return
}
defer response.body.close()

body, err := ioutil.readall(response.body)
if err != nil {
  fmt.println("\033[1;31mcommand > host: could not read response,", err, "\033[0m")
  return
}

fmt.printf("body:\n%s\n", body)
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我们看到以下内容:

{
  "status": false,
  "error": {
    "message": "no file chosen.",
    "type": "error_file_not_provided",
    "code": 10
  }
}
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Copy after login

我们收到此错误是因为您没有在 multipart/form-data 请求中提供 file 参数。 我之前链接到的帖子有几个示例发送多部分请求;我已经测试了其中的几个,它们似乎按预期工作。

您还对 api 返回的响应做出了错误的假设。如果我们使用 curl 发出成功的请求并捕获响应 json,我们会发现它如下所示:

{
  "status": true,
  "data": {
    "file": {
      "url": {
        "full": "https://anonfiles.com/k8cdobwey7/test_txt",
        "short": "https://anonfiles.com/k8cdobwey7"
      },
      "metadata": {
        "id": "k8cdobwey7",
        "name": "test.txt",
        "size": {
          "bytes": 12,
          "readable": "12 b"
        }
      }
    }
  }
}
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请注意,没有 response["url"]response["message"]。如果您想要上传文件的url,则需要获取response["data"]["file"]["url"]["full"](或["short"])。

同样,我们可以看到上面的错误响应示例,如下所示:

{
  "status": false,
  "error": {
    "message": "no file chosen.",
    "type": "error_file_not_provided",
    "code": 10
  }
}
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Copy after login

这不是 result["message"];那是 result["error"]["message"]

因为您要解组到 map[string] 接口 ,所以获取这些嵌套键会有点痛苦。我发现为上述响应创建 go 结构是最简单的,只需将其解组为适当类型的变量即可。

这让我得到以下类型:

type (
  anonfilesurl struct {
    full  string `json:"full"`
    short string `json:"short"`
  }

  anonfilesmetadata struct {
    id   string `json:"id"`
    name string `json:"name"`
    size struct {
      bytes    int    `json:"bytes"`
      readable string `json:"readable"`
    } `json:"size"`
  }

  anonfilesdata struct {
    file struct {
      url      anonfilesurl      `json:"url"`
      metadata anonfilesmetadata `json:"metadata"`
    } `json:"file"`
  }

  anonfileserror struct {
    message string
    type    string
    code    int
  }

  anonfilesresponse struct {
    status bool           `json:"status"`
    data   anonfilesdata  `json:"data"`
    error  anonfileserror `json:"error"`
  }
)
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然后解组响应如下所示:

var result anonfilesresponse
err = json.unmarshal(body, &result)
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我们可以请求以下字段:

fmt.Printf("URL: %s\n", result.Data.File.URL.Full)
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source:stackoverflow.com
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