Convert custom type to basic type pointer

#php editor Baicao today introduces to you an important concept about type conversion - converting a custom type into a basic type pointer. In programming, we often need to convert a custom type into a pointer of a basic type in order to perform some specific operations. This conversion operation can help us process data more flexibly and improve the efficiency and readability of the code. This article will explain this concept in detail and give some examples to help readers better understand and apply it.

Question content

Suppose I have this code:

type CustomStringType string

var a *CustomStringType

x := CustomStringType("sample string")
a = &x


var b *string

I can't modify anything in the code above.

Now I want to assign a to b

I tried multiple methods, such as:

b = a
b = string(a)
b = a.(string)
b = a.(*string)

But none of them really worked.

Solution

Use simple typesConversion:

b = (*string)(a)

Since the type you are converting begins with the * operator, it must be enclosed in parentheses to avoid ambiguity (e.g., you are converting to *string, not string and dereference the result).

(*string)(a) is a valid conversion because you want to convert a value from type *CustomStringType to *string, and The specification allows such conversions using the following rules:

*CustomStringType and *string are both unnamed pointer types, and both have string as their pointer base type.

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