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Home Backend Development Golang Why is ./ automatically inserted in front of the program name when typing a command to run a program?

Why is ./ automatically inserted in front of the program name when typing a command to run a program?

Feb 09, 2024 pm 07:45 PM

Why is ./ automatically inserted in front of the program name when typing a command to run a program?

When running a program using the command line, you may notice that the two characters "./" are automatically inserted in front of the program name. This is because in Unix and Linux systems, "./" represents the current directory. When you type a command to run a program, the system will first look for the program's executable file in the current directory. If you do not add "./", the system will think that you want to run the command that comes with the system or the program in the path specified by the environment variable PATH. Therefore, in order to ensure that the program in the current directory is run, we need to add "./" before the program name. This is a system default behavior that ensures command line security and consistency.

Question content

For example,

package main

import (
   "fmt"
    "net/http"
)

func hello(res http.ResponseWriter, req *http.Request) {
    fmt.Fprint(res, "Hello, my name is Inigo Montoya")
}

func main() {
    http.HandleFunc("/", hello)
    http.ListenAndServe("localhost:4000", nil)
}
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When entering a command, why not automatically convert inigo to ./inigo?

Solution

You need

./inigo
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Because . is not and should not be in your path. . just refers to the current directory.

Assuming you are using bash, as the question tag indicates, this alternative

$pwd/inigo
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also works like any other relative or absolute path to inigo.

edit

Alternatively, you can add $pwd to your path, which has the advantage of not requiring you to type any of the above and not causing the addition of . security risks.

Assuming you are in a directory containing inigo, then

path+=:$pwd
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Then just enter

inigo
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From anywhere.

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