php Editor Xigua encountered an interesting problem when writing a program in Golang: how to print the first input twice in the file. This question seems simple, but it actually involves multiple aspects of knowledge such as how to read input, process strings, and file operations. Through in-depth research and practice, I successfully solved this problem and shared the solution with everyone. Next, I will introduce in detail the steps of my program implementation in Golang.
I try to get some csv formatted string as input and then print it to an actual csv file. It works, but it prints the first string twice.
My code looks like this:
func main() { scanner := bufio.newscanner(os.stdin) n := 0 inputfile, err := os.create("input.csv") //create the input.csv file if err != nil { log.fatal(err) } csvwriter := csv.newwriter(inputfile) fmt.println("how many records ?") fmt.scanln(&n) fmt.println("enter the records") var lines [][]string for i := 0; i < n; i++ { scanner.scan() text := scanner.text() lines = append(lines, []string{text}) err := csvwriter.writeall(lines) if err != nil { return } } csvwriter.flush() inputfile.close() }
For n=2 and records:
abcd, efgh, ijklmn opq, rstu, vwxyz
The output looks like this:
"abcd, efgh, ijklmn" "abcd, efgh, ijklmn" "opq, rstu, vwxyz"
This is my first time using golang and I'm a bit lost :d
You are writing the csv in a loop so that the first line prints double. Here is the corrected code.
package main import ( "bufio" "encoding/csv" "fmt" "log" "os" ) func main() { scanner := bufio.NewScanner(os.Stdin) n := 0 inputFile, err := os.Create("input.csv") //create the input.csv file if err != nil { log.Fatal(err) } defer func() { inputFile.Close() }() csvwriter := csv.NewWriter(inputFile) defer func() { csvwriter.Flush() }() fmt.Println("How many records ?") fmt.Scanln(&n) fmt.Println("Enter the records") var lines [][]string for i := 0; i < n; i++ { scanner.Scan() text := scanner.Text() lines = append(lines, []string{text}) } err = csvwriter.WriteAll(lines) if err != nil { return } }
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