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Home Backend Development Golang How to generate interface implementation in VS Code for Go?

How to generate interface implementation in VS Code for Go?

Feb 11, 2024 am 08:45 AM
go language

如何在 VS Code for Go 中生成接口实现?

When using VS Code for Go language development, generating interface implementations is a common requirement. Interface implementation can help us quickly generate code templates that follow the interface definition and improve development efficiency. So, how to implement this function in VS Code for Go? This article will introduce you to several methods to implement interface generation to help you better use VS Code for Go language development.

Question content

In vscode, how to generate the implementation of the interface?

For example, I have this interface:

type ServerInterface interface {
    // Set value for a device
    SetSomethingForDeviceById(ctx echo.Context, id int64) error
}
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How to generate a method to implement it?

Solution

vscode supports using go extension to generate interface.

The specific operation methods are as follows:

First, start by defining the structure:

type apiserver struct {}
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Now, using ctrl-shift-p, find this command: "gogenerateinterfacestubs"

Now enter the following content: receiver name, type, interface name:

s receivertype package.interfacename

Press the enter key. Generate missing methods:

package api

import "github.com/labstack/echo/v4"

// Set value for a device
func (s ApiServer) SetSomethingForDeviceById(ctx echo.Context, id int64) error {
    panic("not implemented")
}
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@clément-jean added:

This command depends on https://www.php.cn/link/428b8e0c8ae876e78e551367212ae73b: You need to install it before generating code.

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