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MySQL 写SQL吃饭中被call起,帮她解决一个SQL的过程_MySQL

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Release: 2016-06-01 13:26:56
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bitsCN.com

正吃饭中被大学同学call起,帮他同事解决一个复杂的SQL问题

 

1 SHE第一封email:

select distinct Test.Name,Test.ID,Plan_Device.ID from Test,Plan_Device where Test.ID in(select TestID from TestResult where (StatusID=1 || StatusID=2)

and PlanResultID=(select ID from PlanResultwhere Sessionid='tangzm_ASBSH2_20131204_10371' and PlanID=(select ID fromTestPlan where Name='MEG_DS3_RRA_FT_MCM3_003')))

and Test.TestPlanID=Plan_Device.TestPlanID

 

select Test.Name,Test.IDfrom Test,AssociateTest where (AssociateTest.TestID=69721or AssociateTest.AssoccaseID=69721) and

(Test.ID=AssociateTest.AssoccaseID orTest.ID=AssociateTest.TestID);

 

现在有这样两个查询,我需要的字段是第二句中的Test.Name,Test.ID和第一句中的Plan_Device.ID

第二句中的69721应该是第一句中查询结果的Test.ID

请问这个语句应该怎么写呢?

 

 

2 ME第二封email:

SELECT DISTINCTTest.Name,Test.ID,Plan_Device.ID

FROMTest,Plan_Device,AssociateTestWHERE Test.ID IN (SELECT TestID FROM TestResult WHERE (StatusID=1 ||StatusID=2)

AND PlanResultID=(

SELECT ID FROM PlanResult WHERE Sessionid='tangzm_ASBSH2_20131204_10371' ANDPlanID=(SELECT ID FROM TestPlan WHERE NAME='MEG_DS3_RRA_FT_MCM3_003')))

ANDTest.TestPlanID=Plan_Device.TestPlanID

and (AssociateTest.TestID=Test.ID ORAssociateTest.AssoccaseID=Test.ID)

AND (Test.ID=AssociateTest.AssoccaseID ORTest.ID=AssociateTest.TestID);

 

黄色部分是我添加进去的,你看看是否可以运行得到你要的结果。

[备注]:我以为是简单的取值,直接把第三张表关联起来把判断条件加上不就行了吗?

 

3 SHE第三封email:

结果显示和第一句查询的结果相同

 

select Test.Name,Test.IDfrom Test,AssociateTest where (AssociateTest.TestID=69721or AssociateTest.AssoccaseID=69721) and

(Test.ID=AssociateTest.AssoccaseID orTest.ID=AssociateTest.TestID);

应该显示两行结果,一行是AssociateTest.TestID=69721查询出来的,另一行是AssociateTest.AssoccaseID=69721查询出来的

 

[备注] 看到她的回复,再仔细看看她第一封email的描述,我知道了她的意思,不仅仅是简单关联,是要把2个结果集归纳到一起,再取出值,换思路吧。

 

 

4 ME第四封email:

想了想,要使用单独集合了,写了sql,发email给她,你试下下面这个:

 

SELECTTest.Name,Test.ID,TP.Plan_Device_IDFROM Test,AssociateTest,(

SELECTDISTINCT Test.Name,Test.ID,Plan_Device.ID Plan_Device_ID

FROM Test,Plan_DeviceWHERE Test.ID IN (SELECT TestID FROM TestResult WHERE (StatusID=1 ||StatusID=2)

ANDPlanResultID=(

SELECT ID FROM PlanResult WHERE Sessionid='tangzm_ASBSH2_20131204_10371' ANDPlanID=(SELECT ID FROM TestPlan WHERE NAME='MEG_DS3_RRA_FT_MCM3_003')))

ANDTest.TestPlanID=Plan_Device.TestPlanID

)TP

WHERE(AssociateTest.TestID=TP.IDOR AssociateTest.AssoccaseID=TP.ID)AND (Test.ID=AssociateTest.AssoccaseID OR Test.ID=AssociateTest.TestID);

 

 

5SHE第五封email:

 

这个可以用, 谢谢!

 

OK,搞定了。

bitsCN.com
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