How to convert JSON string to PHP object?

JSON is a lightweight data exchange format commonly used for front-end and back-end data transmission. In PHP, you can use the built-in json_decode() function to convert a JSON string into a PHP object. Next, specific methods and code examples will be introduced.

In PHP, the json_decode() function can accept a JSON-formatted string as a parameter and convert it into a PHP object or array (depending on the second parameter passed in), as shown below:

$json_string = '{"name": "John", "age": 30, "city": "New York"}';
$php_object = json_decode($json_string);

The above code example converts a JSON string $json_string into a PHP object $php_object. Now, the data can be obtained by accessing the properties of the object, for example:

echo $php_object->name;  // 输出：John
echo $php_object->age;   // 输出：30
echo $php_object->city;  // 输出：New York

If you wish to convert the JSON string to a PHP associative array, you can set the second parameter of json_decode() to true as shown below :

$json_string = '{"name": "Alice", "age": 25, "city": "Los Angeles"}';
$php_array = json_decode($json_string, true);

With the above code example, the JSON string $json_string is converted into a PHP associative array $php_array. Now, the data can be accessed through the keys of the array, for example:

echo $php_array['name'];  // 输出：Alice
echo $php_array['age'];   // 输出：25
echo $php_array['city'];  // 输出：Los Angeles

It should be noted that when processing JSON strings, the json_decode() function will return null if the string format is incorrect or the parsing fails. Therefore, in actual use, the return value needs to be checked to ensure that the data can be converted correctly.

The above are methods and code examples for converting JSON strings into PHP objects or arrays. I hope this article can help you better understand and use JSON conversion operations in PHP.

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