


In-depth understanding of character and integer conversion in Golang
Go 语言中字符和整型可通过以下方式转换:字符转整型:使用 strconv.Atoi() 将字符串转换为十进制整型。整型转字符:使用 strconv.Itoa() 将整型转换为十进制字符串,该整型值会被视为 ASCII 码值。实战案例:进制转换:使用 strconv.ParseInt() 和 strconv.FormatInt() 转换不同进制的整型。ASCII 码转换:使用 byte() 和 int() 将字符和 ASCII 码值进行互相转换。
深入理解 Go 中字符和整型的转换
在 Go 语言中,字符和整型之间的转换是常见任务。本篇文章将深入解析这些转换背后的机制并提供实战案例。
字符转整型
strconv.Atoi()
函数可将字符串转换为整型:
import "strconv" func CharToInt(char byte) (int, error) { return strconv.Atoi(string(char)) }
整型转字符
strconv.Itoa()
函数可将整型转换为字符串:
func IntToChar(num int) byte { return num + '0' // ‘0’ 的 ASCII 值为 48 }
实战案例
进制转换
func ConvertBase(num string, fromBase, toBase int) (string, error) { i, err := strconv.ParseInt(num, fromBase, 64) if err != nil { return "", err } return strconv.FormatInt(i, toBase), nil }
ASCII 码转换
func AsciiToChar(ascii int) byte { return byte(ascii) } func CharToAscii(char byte) int { return int(char) }
注意
-
strconv.ParseInt()
和strconv.FormatInt()
可处理不同进制的整型(例如二进制、八进制、十进制等)。 -
strconv.Atoi()
和strconv.Itoa()
仅处理十进制整型。 - 如果字符串不是有效的整型表示,
strconv.Atoi()
和strconv.ParseInt()
会返回错误。
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