Strings in the Go language are immutable, that is, the content cannot be modified after creation, and a copy will be created for each modification operation. This affects join operations (need to use or strings.Join), local variables (need to be careful about scope when manipulating strings), and optimization (the compiler can perform optimizations to improve performance). When concatenating strings, use bytes.Buffer to avoid copy creation.
String is an indispensable data type in programming, and string performance in Golang It has a very interesting property: it is immutable. This is different from the mutable strings we encounter in many other languages, and can have a significant impact on our coding patterns.
In Golang, strings are immutable, which means that once a string is created, its content cannot be modified. Instead, any modification to a string creates a new copy of the string.
For example:
s := "Hello" s[0] = 'H' // 会引发错误:cannot assign to s[0]
This code tries to modify the first character in the string s
, but it throws a compile-time error because s
is immutable.
String immutability will have some impact on our coding practices:
operator or the strings.Join
function. This causes a copy of the string to be created. Let’s look at a practical case to demonstrate how to effectively concatenate strings:
// 不可取的做法:重复创建字符串副本 var s = "" for i := 0; i < 100; i++ { s += strconv.Itoa(i) // 会创建 100 个字符串副本 } // 更好的做法:使用 bytes.Buffer var b bytes.Buffer for i := 0; i < 100; i++ { b.WriteString(strconv.Itoa(i)) // 不会创建任何字符串副本 }
In the first code snippet , we repeatedly create a copy of the string to concatenate the strings, which incurs a large performance overhead. And in the second code snippet, we use bytes.Buffer
to avoid creating a copy.
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