How to use C++ function templates to genericize function pointers?

C function template allows generalization of function pointers and supports function pointers of different types of parameters. The specific steps are as follows: declare a function template with a function pointer, where T is the template type parameter. Pass the function pointer to be generalized as a parameter to the template function. Template functions return generic function pointers.

Use C function templates to achieve generalization of function pointers

Introduction

C Function pointers provide a way to pass functions as parameters or return values. However, if you want to create function pointers that support different types of parameters, you need to use function templates. Function templates can generate different versions of a function with parameters of specific types.

Function Template Syntax

Here's how to declare a function template with a function pointer:

template <typename T>
auto make_function_pointer(T function) {
  return function;
}

Where:

• T is a template parameter of the type to use. It can be of any type, including function pointer types.
• function is the function pointer to be generic.

Practical Case

Let us create a generic function pointer that can receive any type of function and return it as an integer.

#include <iostream>

template <typename T>
int generic_function_pointer(T function) {
  return function();
}

int main() {
  // 定义一个函数，返回一个整数
  int my_function() {
    return 10;
  }

  // 创建一个泛型函数指针
  auto function_ptr = generic_function_pointer(my_function);

  // 调用函数指针
  int result = function_ptr();

  std::cout << "Result: " << result << std::endl;

  return 0;
}

Output

Result: 10

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