Compatibility rules for Java function generics
The compatibility rules of Java function generics ensure type safety. Rules include: same type parameter lists, same type parameter bounds, and contravariant and covariant type parameters. For example, <List<Cat>> is compatible with <List<Animal>> (contravariant), while <String> is compatible with <Object> (covariant).
Compatibility rules for Java function generics
Java generic functions allow us to write code in a type-safe manner, But not following the correct compatibility rules can lead to compile-time errors. Let’s sort out the rules to avoid such problems.
Rule 1: The type parameter lists are the same
Only function types with the same parameter list are compatible. So the following example will result in an error:
public <T> void func1(T v) {} public <U> void func2(U v) {}
Rule 2: Type parameters have the same bounds
Bounds define the allowed values of a generic type. Functions are incompatible if they have different bounds for parameters of the same type. For example:
public <T extends Comparable<T>> void func1(T v) {} public <T extends Number> void func2(T v) {}
Rule 3: Contravariant and covariant type parameters
- Contravariance: If subclass type T can replace superclass type S, then
<T>
is type compatible with<S>
. For example,<List<Cat>>
is compatible with<List<Animal>>
. - Covariance: If the superclass type T can replace the subclass type S, then the
<S>
type is compatible with<T>
. For example,<String>
is compatible with<Object>
.
Practical case
Consider the following code:
public <T extends Animal> void func1(T t) { // 代码... } public void func2(Cat c) { // 代码... }
func1
Expects an Animal
or an instance of its subclass. func2
Expects a Cat
instance. Since Cat
extends Animal
, func1
is compatible with func2
and can receive Cat
type parameters.
Conclusion
It is crucial to follow the compatibility rules for function generics to avoid compile-time errors and ensure type safety.
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