int is a primitive data type used to store integers in Java. The number of bytes it occupies depends on the number of bits in the JVM: 32-bit JVM: 4 bytes 64-bit JVM: 8 bytes Its range Depends on JVM bitness, for example: 32-bit JVM: -2^31 to 2^31-164-bit JVM: -2^63 to 2^63-1
How many bytes does int occupy in Java?
int is a primitive data type in Java used to store integers. In a 32-bit Java Virtual Machine (JVM), an int occupies 4 bytes, while in a 64-bit JVM, an int occupies 8 bytes.
Why do the number of bytes occupied in different JVMs differ?
JVM is an abstract computing environment that defines a bytecode instruction set and runtime environment. A 32-bit JVM has a 32-bit address bus and data bus, while a 64-bit JVM has a 64-bit address bus and data bus.
The address bus determines the maximum amount of memory that the JVM can address, and the data bus determines the maximum amount of data that the JVM can process at one time. In a 32-bit JVM, the data bus is 32 bits, so 4 bytes can be processed at a time; in a 64-bit JVM, the data bus is 64 bits, so 8 bytes can be processed at a time.
Range of int
The range of int depends on the bitness of the JVM. In a 32-bit JVM, the range of int is -2^31 to 2^31-1 (approximately -2.1 billion to 2.1 billion). In a 64-bit JVM, the range of int is -2^63 to 2^63-1 (approximately -9200 billion to 9200 billion).
Usage scenarios of int
int is used to store various integer values, for example:
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