Home > Java > javaTutorial > body text

How to use scanf in java

下次还敢
Release: 2024-05-01 19:48:54
Original
1265 people have browsed it

There is no scanf function in Java. Use the Scanner class to read data. The steps are: import the java.util.Scanner package, create a Scanner object, use nextInt() and other methods to read data, and finally close the Scanner object.

How to use scanf in java

There is no scanf function in Java

There is no direct corresponding scanf function in the Java language. Instead, Java uses the Scanner class to read data from the input stream.

Usage of the Scanner class

To use the Scanner class, you need to follow the following steps:

  1. Importjava.util.Scanner package.
  2. Create a Scanner object that will be associated with the input stream to be read.
  3. Use methods on the Scanner object (such as nextInt(), nextDouble() or nextLine()) Read data.
  4. Close the Scanner object and release resources.

Sample Code

The following example demonstrates how to read integer numbers using the Scanner class in Java:

<code class="java">import java.util.Scanner;

public class ReadInteger {

    public static void main(String[] args) {
        // 创建一个 Scanner 对象,该对象从控制台读取输入
        Scanner scanner = new Scanner(System.in);

        // 提示用户输入整数
        System.out.print("请输入一个整数:");

        // 使用 nextInt() 方法从控制台读取整数
        int number = scanner.nextInt();

        // 打印输入的整数
        System.out.println("你输入的整数是:" + number);

        // 关闭 Scanner 对象
        scanner.close();
    }
}</code>
Copy after login

Conclusion

In Java, there is no direct corresponding scanf function. Instead, the Scanner class is used to read data from the input stream, using methods such as nextLine(), nextInt(), etc. to get each element from the console on demand. data type.

The above is the detailed content of How to use scanf in java. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template