Table of Contents
数据库的数据更新
请输放需要更改的id:
Home Backend Development PHP Tutorial 桌面中心(三) 修改数据库

桌面中心(三) 修改数据库

Jun 01, 2016 pm 02:31 PM

下面这个程序在你输入id后就把那个id的数据列出来。然后你就可以修改后写入了.


数据库的数据更新



if(isset($id))
{
if(!MySQL_connect("localhost","用户名","密码"))
{echo"无法联接数据库";
exit();
}
if(isset($url))
{
$query="update $jpg set id='$id',url='$url',mess='$mess',
fromx='$fromx',url1='$url1',mess1='$mess1',fromx1='$fromx1',url2='$url2',
mess2='$mess2',fromx2='$fromx2',url3='$url3',mess3='$mess3',fromx3='$fromx3'
where id='$id'" ;
$result=mysql_db_query("elong",$query); //执行写入

if (!$result)
{echo "发生错误!";
exit();
}
echo "$id 已经更新!

";
echo "n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
ID $id
url地址 $url
小图 $mess
说明 $fromx
url地址1 $url1
小图1 $mess1
说明1 $fromx1
url地址2 $url2
小图2 $mess2
说明2 $fromx2
url地址3 $url3
小图3 $mess3
说明3 $fromx3
n";
echo "回到首页";
exit();
}
$query="SELECT id,url,mess,fromx,url1,mess1,fromx1,url2,mess2,fromx2,url3,mess3,fromx3 from $jpg
where id='$id'" ;
$result=mysql_db_query("elong",$query);
if (!$result)
{echo "发生错误!";
exit();
}
$r=mysql_fetch_array($result);
$id = $r["id"];
$url = $r["url"];
$mess = $r["mess"];
$fromx = $r["fromx"];
$url1 = $r["url1"];
$mess1 = $r["mess1"];
$fromx1 = $r["fromx1"];
$url2 = $r["url2"];
$mess2 = $r["mess2"];
$fromx2 = $r["fromx2"];
$url3 = $r["url3"];
$mess3 = $r["mess3"];
$fromx3 = $r["fromx3"];
echo"
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
ID:
类形:
图片url地址:
说明:
来自:
图片url地址:
说明:
来自:
图片url地址:
说明:
来自:
图片url地址:
说明:
来自:
n
n
n";
}
else
{?>

请输放需要更改的id:





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其它类







}?>




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