The constexpr keyword in C allows the declaration of constant expression functions that are evaluated at compile time and produce a constant result. This provides the benefits of compile-time evaluation, optimization opportunities, and protection against accidental modifications. The syntax is: constexpr <return_type> function_name (parameter list). Practical case: constexpr int factorial(int n) { if (n == 0) { return 1; } else { return n * factorial(n - 1); } }
In C, the constexpr
keyword allows you to declare constant expression functions that are evaluated at compile time and produces constant results. This provides the following benefits:
constexpr
The syntax of function declaration is as follows:
constexpr <return_type> function_name(参数列表);
Among them:
<return_type>
is the constant value type returned by the function. function_name
is the function name. Parameter list
is the constant expression parameter accepted by the function. The following is a code example using the constexpr
constant expression function:
constexpr int factorial(int n) { if (n == 0) { return 1; } else { return n * factorial(n - 1); } } int main() { constexpr int result = factorial(5); // 在编译时求值 factorial(5) 并存储在 result 中 std::cout << "5 的阶乘为:" << result << std::endl; return 0; }
In this example, ## The #factorial function is a constant expression function that computes the factorial of a number using a recursive algorithm.
main The
constrent static declaration in the function allows the result of
factorial(5) to be calculated at compile time and stored in a
result constant middle.
functions.
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