求助:关于php一段简单代码

WBOY
Release: 2016-06-02 11:32:28
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这是php和mysql web开发书中一个例子,目的就是把文件保存的订单信息炸开,用表格显示。我运行时为什么只显示表头,没有表格数据呢。
orders.txt中就是订单信息,用Tab分隔的,已正确读取到$orders中。貌似是后边的for循环中有问题。图片说明



Bob's Auto Parts - Customer Orders

Bob's Auto Parts

Customer Orders

//Read the entire file
//Each order becomes an element in the array
$orders = file("./orders.txt");

<code>//count the number of orders in the array$number_of_orders = count($orders);if($number_of_orders = 0) {    echo "<p><strong>No orders pending. Please try again later.</strong></p>";}echo "<table border='\"1\"'>\n";echo "<tr>
<th bgcolor='\"#CCCCFF\"'>Order Date</th>          <th bgcolor='\"#CCCCFF\"'>Tires</th>          <th bgcolor='\"#CCCCFF\"'>Oil</th>          <th bgcolor='\"#CCCCFF\"'>Spark plugs</th>          <th bgcolor='\"#CCCCFF\"'>Total</th>          <th bgcolor='\"#CCCCFF\"'>Address</th>      </tr>";for($i = 0; $i             <td>".$line[0]."</td>            <td align='\"right\"'>".$line[1]."</td>            <td align='\"right\"'>".$line[2]."</td>            <td align='\"right\"'>".$line[3]."</td>            <td align='\"right\"'>".$line[4]."</td>            <td>".$line[5]."</td>          ";}echo "</table>";</code>
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?>

<code></code>
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