php-ecshop获取端口的疑问

WBOY
Release: 2016-06-02 11:33:46
Original
964 people have browsed it

php

<code>   if (isset($_SERVER['SERVER_PORT']))            {                $port = ':' . $_SERVER['SERVER_PORT'];                if ((':80' == $port && 'http://' == $protocol) || (':443' == $port && '                          https://' == $protocol))                {                    $port = '';                }            }</code>
Copy after login

其中

<code>  if ((':80' == $port && 'http://' == $protocol) ||        (':443' == $port && 'https://' == $protocol))                {                    $port = '';                }</code>
Copy after login

这段代码的意思作用是什么? 如果条件成立,为什么要把$port 设置为空?

整个函数的代码:

<code> function get_domain()    {        /* 协议 */        $protocol = $this->http();        /* 域名或IP地址 */        if (isset($_SERVER['HTTP_X_FORWARDED_HOST']))        {            $host = $_SERVER['HTTP_X_FORWARDED_HOST'];        }        elseif (isset($_SERVER['HTTP_HOST']))        {            $host = $_SERVER['HTTP_HOST'];        }        else        {            /* 端口 */            if (isset($_SERVER['SERVER_PORT']))            {                $port = ':' . $_SERVER['SERVER_PORT'];                if ((':80' == $port && 'http://' == $protocol) || (':443' == $port && 'https://' == $protocol))                {                    $port = '';                }            }            else            {                $port = '';            }            if (isset($_SERVER['SERVER_NAME']))            {                $host = $_SERVER['SERVER_NAME'] . $port;            }            elseif (isset($_SERVER['SERVER_ADDR']))            {                $host = $_SERVER['SERVER_ADDR'] . $port;            }        }        return $protocol . $host;    }</code>
Copy after login
Related labels:
php
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!