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时间-time() - date('Z')有什么用？为什么date('Z')的值是0？

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Release： 2016-06-02 11:33:47
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时间phpdatetime时区 

<code> /** * 获得当前格林威治时间的时间戳 * * @return  integer */function gmtime(){    return (time() - date('Z'));}</code>
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看到一个函数的作用是获得当前格林威治时间的时间戳
为什么我echo date('Z') 输出的值是0？
我们不是北京时间吗。date(''Z'')是时区偏移秒数，应该不是0才对

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时间 php date time 时区
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