Home > php教程 > php手册 > body text

php给$

WBOY
Release: 2016-06-06 19:46:57
Original
1435 people have browsed it

在调试一个程序的时候发现很奇怪的现象,post传过来的值再某些地方为空,先看下面的代码 1 ? php 2 if ( $_POST ['submit'] == 'Add' ){ 3 if ( $_POST ['type']='movie' $_POST ['movie_type'] == '' ){ 4 header ('Location:form4.php' ); 5 } 6 } 7 ? 8 h

在调试一个程序的时候发现很奇怪的现象,post传过来的值再某些地方为空,先看下面的代码

<span> 1</span> <span>php 
</span><span> 2</span> <span>if</span>(<span>$_POST</span>['submit'] == 'Add'<span>){
</span><span> 3</span>     <span>if</span>(<span>$_POST</span>['type']='movie' && <span>$_POST</span>['movie_type'] == ''<span>){
</span><span> 4</span>         <span>header</span>('Location:form4.php'<span>);
</span><span> 5</span> <span>    }
</span><span> 6</span> <span>}
</span><span> 7</span> ?>
<span> 8</span> 
<span> 9</span>      
<span>10</span>     <title>Multipurpose Form</title>
<span>11</span>     
<span>12</span>     
<span>13</span>         <span>php 
</span><span>14</span>         
<span>15</span>         <span>if</span>(<span>$_POST</span>['submit'] == 'Add'<span>){
</span><span>16</span>             <span>echo</span> '<h1>Add '.<span>ucfirst</span>(<span>$_POST</span>['type']).'</h1>'<span>;
</span><span>17</span>         ?>
<span>18</span>         
Copy after login
19 20 2122232627php 2829if($_POST['type'] == 'movie') {?> 30313233343536373839else 40 { echo ''; } 41 ?> 424344455354
Name echo $_POST['name']?> 24 25
Movie type echo $_POST['movie_type']?>
Year
Movie Description
Biography
46 php 47 if(isset($_POST['debug'])){ 48 echo ''; 49 } 50 ?> 51 52
55
56 php 57 } 58 else if($_POST['submit']=='Search'){ 59 echo '

Search for '.ucfirst($_POST["type"]).'

'; 60 echo '

Searching for '.$_POST["name"].'...

'; 61 } 62 63 if(isset($_POST['debug'])){ 64 echo '
'<span>;
</span><span>65</span>             <span>print_r</span>(<span>$_POST</span><span>);
</span><span>66</span>             <span>echo</span> '
Copy after login
'; 67 } 68 ?> 69 70

在第29行是要根据上一个页面传递过来的值来输出信息的,但是即使传递过来的值是movie,还是没有输出想要的值,我我在很多地方都添加了echo($_POST['type']);这一句话发先在代码最顶端还能输出movie 的,第二行下面还是能够输出,就是在第三行下面就没有值了,这里你可能也发现错误了,if($_POST['type']='movie',这一句,本来是判断语句,结果少写了一个等号变成了赋值语句,初学者错误啊!!!!!!

正确的写法应该是if($_POST['type']=='movie' && $_POST['movie_type'] == '')

<br><br>
Copy after login
Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Recommendations
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!