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JSON在php中的使用

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Release: 2016-06-06 19:53:14
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欢迎进入Linux社区论坛,与200万技术人员互动交流 >>进入 json_encode() 该函数主要用来将数组和对象,转换为json格式。 $arr = array ('a'='a','b'='b','c'='c','d'='d','e'='e'); echo json_encode($arr); json只接受utf-8编码的字符,json_encode

欢迎进入Linux社区论坛,与200万技术人员互动交流 >>进入

  json_encode()

  该函数主要用来将数组和对象,转换为json格式。

  $arr = array ('a'=>'a','b'=>'b','c'='c','d'=>'d','e'='e');

  echo json_encode($arr);

  json只接受utf-8编码的字符,json_encode()的参数必须是utf-8编码。

  复制代码

  class person

  {

  public $name;

  public $age;

  public $height;

  function __construct($name,$age,$height)

  {

  $this->name = $name;

  $this->age = $age;

  $this->height = $height;

  }

  }

  $obj = new person("zhangsan",20,100);

  $foo_json = json_encode($obj);

  echo $foo_json;

  当类中的属性为私有变量的时候,则不会输出。

  json_decode()

  该函数用于将json文本转换为相应的PHP数据结构。

  $json = '{"a":"hello","b":"world","c":"zhangsan","d":20,"e":170}';

  var_dump(json_decode($json));

  通常情况下,json_decode()总是返回一个PHP对象。

  转成数组的:

  $json = '{"a":"hello","b":"world","c":"zhangsan","d":20,"e":170}';

  var_dump(json_decode($json,ture));

JSON在php中的使用

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