Home > php教程 > php手册 > PHP实现身份证验证函数

PHP实现身份证验证函数

WBOY
Release: 2016-06-06 19:56:48
Original
1122 people have browsed it

欢迎进入Linux社区论坛,与200万技术人员互动交流 >>进入 PHP实现身份证验证函数 function validation_filter_id_card($id_card){ if(strlen($id_card) == 18) { return idcard_checksum18($id_card); }elseif((strlen($id_card) == 15)){ $i

欢迎进入Linux社区论坛,与200万技术人员互动交流 >>进入

  PHP实现身份证验证函数

  function validation_filter_id_card($id_card){

  if(strlen($id_card) == 18) {

  return idcard_checksum18($id_card);

  }elseif((strlen($id_card) == 15)){

  $id_card = idcard_15to18($id_card);

  return idcard_checksum18($id_card);

  }else{

  return false;

  }

  }

  // 计算身份证校验码,根据国家标准GB 11643-1999

  function idcard_verify_number($idcard_base){

  if(strlen($idcard_base) != 17){

  return false;

  }

  //加权因子

  $factor = array(7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2);

  //校验码对应值

  $verify_number_list = array('1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2');

  $checksum = 0;

  for ($i = 0; $i

  $checksum += substr($idcard_base, $i, 1) * $factor[$i];

  }

  $mod = $checksum % 11;

  $verify_number = $verify_number_list[$mod];

  return $verify_number;

  }

  // 将15位身份证升级到18位

  function idcard_15to18($idcard){

  if (strlen($idcard) != 15){

  return false;

  }else{

  // 如果身份证顺序码是996 997 998 999,这些是为百岁以上老人的特殊编码

  if (array_search(substr($idcard, 12, 3), array('996', '997', '998', '999')) !== false){

  $idcard = substr($idcard, 0, 6) . '18'. substr($idcard, 6, 9);

  }else{

  $idcard = substr($idcard, 0, 6) . '19'. substr($idcard, 6, 9);

  }

  }

  $idcard = $idcard . idcard_verify_number($idcard);

  return $idcard;

  }

  // 18位身份证校验码有效性检查

  function idcard_checksum18($idcard){

  if (strlen($idcard) != 18){

  return false;

  }

  $idcard_base = substr($idcard, 0, 17);

  if(idcard_verify_number($idcard_base) != strtoupper(substr($idcard, 17, 1))){

  return false;

  }else{

  return true;

  }

  }

PHP实现身份证验证函数

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Recommendations
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template