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Home Backend Development PHP Tutorial PHP 全局和静态变量的引用问题?

PHP 全局和静态变量的引用问题?

Jun 06, 2016 pm 08:06 PM
php

哪位大神能从内存的角度解释下 php 官方手册上的这个例子,我是个初级 PHPer 搞不太明白,请前辈不吝赐教,晚辈不胜感谢!

最好能下面代码运行时的内存的情况说明下。

类似的行为也适用于 static 语句。引用并不是静态地存储的:

function &get_instance_ref() {
    static $obj;

    echo 'Static object: ';
    var_dump($obj);
    if (!isset($obj)) {
        // 将一个引用赋值给静态变量
        $obj = &new stdclass;
    }
    $obj->property++;
    return $obj;
}

function &get_instance_noref() {
    static $obj;

    echo 'Static object: ';
    var_dump($obj);
    if (!isset($obj)) {
        // 将一个对象赋值给静态变量
        $obj = new stdclass;
    }
    $obj->property++;
    return $obj;
}

$obj1 = get_instance_ref();
$still_obj1 = get_instance_ref();
echo "\n";
$obj2 = get_instance_noref();
$still_obj2 = get_instance_noref();
Copy after login
Copy after login

以上例程会输出:

Static object: NULL
Static object: NULL

Static object: NULL
Static object: object(stdClass)(1) {
["property"]=>
int(1)
}
Copy after login
Copy after login

上例演示了当把一个引用赋值给一个静态变量时,第二次调用 &get_instance_ref() 函数时其值并没有被记住。

本例出处:http://php.net/manual/en/language.variables.scope.php

回复内容:

哪位大神能从内存的角度解释下 php 官方手册上的这个例子,我是个初级 PHPer 搞不太明白,请前辈不吝赐教,晚辈不胜感谢!

最好能下面代码运行时的内存的情况说明下。

类似的行为也适用于 static 语句。引用并不是静态地存储的:

function &get_instance_ref() {
    static $obj;

    echo 'Static object: ';
    var_dump($obj);
    if (!isset($obj)) {
        // 将一个引用赋值给静态变量
        $obj = &new stdclass;
    }
    $obj->property++;
    return $obj;
}

function &get_instance_noref() {
    static $obj;

    echo 'Static object: ';
    var_dump($obj);
    if (!isset($obj)) {
        // 将一个对象赋值给静态变量
        $obj = new stdclass;
    }
    $obj->property++;
    return $obj;
}

$obj1 = get_instance_ref();
$still_obj1 = get_instance_ref();
echo "\n";
$obj2 = get_instance_noref();
$still_obj2 = get_instance_noref();
Copy after login
Copy after login

以上例程会输出:

Static object: NULL
Static object: NULL

Static object: NULL
Static object: object(stdClass)(1) {
["property"]=>
int(1)
}
Copy after login
Copy after login

上例演示了当把一个引用赋值给一个静态变量时,第二次调用 &get_instance_ref() 函数时其值并没有被记住。

本例出处:http://php.net/manual/en/language.variables.scope.php

用静态方式调用一个非静态方法会导致一个 E_STRICT 级别的错误。

就像其它所有的 PHP 静态变量一样,静态属性只能被初始化为文字或常量,不能使用表达式。所以可以把静态属性初始化为整数或数组,但不能初始化为另一个变量或函数返回值,也不能指向一个对象。
出处:http://php.net/manual/zh/language.oop5.static.php

所以global和static不用使用引用赋值,这是由php解释器决定的。

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