Home > Backend Development > PHP Tutorial > preg_replace - ecshop在php5.6下的错误。

preg_replace - ecshop在php5.6下的错误。

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Release: 2016-06-06 20:09:32
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ecshop在php5.6下的错误。在5.3下是正常的。应该是PHP高版本函数变化了。

错误提示:

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/wwwroot/www.ufeelwine.com/includes/cls_template.php on line 1061

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/wwwroot/www.ufeelwine.com/includes/cls_template.php on line 483

具体网页地址:
http://www.ufeelwine.com/supplier.php?suppId=7

第483行:

<code>                    $out = "<?php \n" . '$k = ' . preg_replace("/(\'\\$[^,]+)/e" , "stripslashes(trim('\\1','\''));", var_export($t, true)) . ";\n";
                    $out .= 'echo $this->_echash . $k[\'name\'] . \'|\' . serialize($k) . $this->_echash;' . "\n?>";
</code>
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第1061行:

<code>            $pattern     = '/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/se';
            $replacement = "'{include file='.strtolower('\\1'). '}'";
            $source      = preg_replace($pattern, $replacement, $source);</code>
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应该怎么改写呢?

回复内容:

ecshop在php5.6下的错误。在5.3下是正常的。应该是PHP高版本函数变化了。

错误提示:

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/wwwroot/www.ufeelwine.com/includes/cls_template.php on line 1061

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/wwwroot/www.ufeelwine.com/includes/cls_template.php on line 483

具体网页地址:
http://www.ufeelwine.com/supplier.php?suppId=7

第483行:

<code>                    $out = "<?php \n" . '$k = ' . preg_replace("/(\'\\$[^,]+)/e" , "stripslashes(trim('\\1','\''));", var_export($t, true)) . ";\n";
                    $out .= 'echo $this->_echash . $k[\'name\'] . \'|\' . serialize($k) . $this->_echash;' . "\n?>";
</code>
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第1061行:

<code>            $pattern     = '/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/se';
            $replacement = "'{include file='.strtolower('\\1'). '}'";
            $source      = preg_replace($pattern, $replacement, $source);</code>
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应该怎么改写呢?

//-- 原本

<code>return preg_replace("/{([^\}\{\n]*)}/e", "\$this->select('\\1');", $source);
</code>
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//-- 修改成

<code>return preg_replace_callback("/{([^\}\{\n]*)}/", function($r) { return $this->select($r[1]); }, $source);
</code>
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//-- 原本

<code>$val = preg_replace("/\[([^\[\]]*)\]/eis", "'.'.str_replace('$','\$','\\1')", $val);
</code>
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//-- 修改成

<code>$val = preg_replace_callback("/\[([^\[\]]*)\]/is", function($r) { return '.'.$r[1]; }, $val);
</code>
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//-- 原本

<code>$out = "<?php \n" . '$k = ' . preg_replace("/(\'\\$[^,]+)/e" , "stripslashes(trim('\\1','\''));", var_export($t, true)) . ";\n";
</code></code>
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//-- 修改成

<code>$out = "<?php \n" . '$k = ' . preg_replace_callback("/(\'\\$[^,]+)/" , function($r) { return stripslashes(trim($r[1],'\'')); }, var_export($t, true)) . ";\n";
</code></code>
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//--- 原本

<code>$pattern     = '/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/se';
$replacement = "'{include file='.strtolower('\\1'). '}'";
$source      = preg_replace($pattern, $replacement, $source);
</code>
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//--- 修改成

<code>$pattern     = '/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/s';
$replacement = function ($r) { return '{include file='.strtolower($r[1]). '}'; };
$source      = preg_replace_callback($pattern, $replacement, $source);</code>
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试试,没有环境没办法测试,根据提示信息改的

第483行:改成

<code>$out = "<?php \n" . '$k = ' . preg_replace_callback("/(\'\\$[^,]+)/e" , function($r) { return stripslashes(trim('\\1','\'')); }, var_export($t, true)) . ";\n";</code></code>
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第1061行:改成

<code>//$pattern     = '/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/se';
//$replacement = "'{include file='.strtolower('\\1'). '}'";
$source      = preg_replace('/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/se', function($r) { return '{include file='.strtolower('\\1'). '}';}, $source);</code>
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提示很清楚了啊
把preg_replace换成preg_replace_callback
看看preg_replace_callback的用法就明白了

<code class="php">/*
1、e参数去掉
2、后面的\1换成回调的数组对应的元素
*/
//483行
$out = "<?php \n" . '$k = ' . preg_replace_callback("/(\'\\$[^,]+)/" ,function($r) { return stripslashes(trim($r[1],'\'')); }, var_export($t, true)) . ";\n";</code></code>
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