tp框架能开发API接口吗
最近在做毕业设计,原来学过php,打算用tp框架做,但是现在主流的开发模式使用面向接口的开发,tp框架主要是用模板引擎来渲染页面,不知道tp框架中如何写接口?
回复内容:
最近在做毕业设计,原来学过php,打算用tp框架做,但是现在主流的开发模式使用面向接口的开发,tp框架主要是用模板引擎来渲染页面,不知道tp框架中如何写接口?
答案是必然的,你可以翻看tp手册,里面有一节讲的关于restful接口的操作和写法
你的问题和
‘’php能开发api接口吗‘’没有任何区别。
TP的controller
其实有很多种的HproseController
,JsonRpcController
,RestController
,RpcController
,YarController
我拿RestController给你介绍一下
RESTFul方法的操作方法定义主要区别在于,需要对请求类型和资源类型进行判断,大多数情况下,通过路由定义可以把操作方法绑定到某个请求类型和资源类型。如果你没有定义路由的话,需要自己在操作方法里面添加判断代码,示例:
namespace Home\Controller; use Think\Controller\RestController; Class InfoController extends RestController { Public function rest() { switch ($this->_method){ case 'get': // get请求处理代码 if ($this->_type == 'html'){ }elseif($this->_type == 'xml'){ } break; case 'put': // put请求处理代码 break; case 'post': // post请求处理代码 break; } } }
在Rest操作方法中,可以使用$this->_type获取当前访问的资源类型,用$this->_method获取当前的请求类型。
REST控制器类还提供了response方法用于REST输出: 用法如下:
$this->response($data,'json');
Response方法会自动对data数据进行输出类型编码,目前支持的包括xml/json/html。
除了普通方式定义Restful操作方法外,系统还支持另外一种自动调用方式,就是根据当前请求类型和资源类型自动调用相关操作方法。
要使用这种方式的前提就是不能为当前操作定义方法,这样在空操作的检查之前系统会首先按照上面的定义规范顺序检查是否存在方法定义,如果检测到相关的restful方法则不再检查后面的方法规范,例如我们定义了InfoController如下:
namespace Home\Controller; use Think\Controller\RestController; Class InfoController extends RestController { protected $allowMethod = array('get','post','put'); // REST允许的请求类型列表 protected $allowType = array('html','xml','json'); // REST允许请求的资源类型列表 Public function read_get_html(){ // 输出id为1的Info的html页面 } Public function read_get_xml(){ // 输出id为1的Info的XML数据 } Public function read_xml(){ // 输出id为1的Info的XML数据 } Public function read_json(){ // 输出id为1的Info的json数据 } }
如果我们访问的URL是:
http://www.domain.com/Info/read/id/1.xml
假设我们没有定义路由,这样访问的是Info控制器的read操作,那么上面的请求会调用InfoController类的 read_get_xml方法,而不是read_xml方法,但是如果访问的URL是:
http://www.domain.com/Info/read/id/1.jso...
那么则会调用read_json方法。
如果我们访问的URL是
http://www.domain.com/Info/read/id/1.rss
由于我们不允许rss资源类型的访问,所以,调用的方法其实是read_html方法。

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