如何计算开学第几周, 要求每年通用
其实是要精确到周即可, 即给定当前时间, 知道是本学期的开学第几周. 问题的关键好像是没找到规律, 我现在用的是如下代码(php), 准确度不够好:
<code>function teachweek ($date){ $timestamp=strtotime($date); if (date('m', $timestamp)>=9){ return date('W', $timestamp)-35; }elseif(date('m', $timestamp)</code>
回复内容:
其实是要精确到周即可, 即给定当前时间, 知道是本学期的开学第几周. 问题的关键好像是没找到规律, 我现在用的是如下代码(php), 准确度不够好:
<code>function teachweek ($date){ $timestamp=strtotime($date); if (date('m', $timestamp)>=9){ return date('W', $timestamp)-35; }elseif(date('m', $timestamp)</code>
不准确的问题应该出在35、18这几个数字上,另外,如果9月1日是星期六或者星期日的话,也不能算作第一周,所以,可以先判断当年9月1日是在第几周
<code>$thisyear=date('Y',strtotime($date)); $ondate=date('W',strtotime("1 September $thisyear"));</code>
这样,第四行就能替换成
<code>return date('W', $timestamp)-$ondate+1;</code>
是否+1需要通过对9月1日是否为周六/日判断确定,这儿具体就不写了;
如果日期是年初寒假之前,还需要跨年计算去年9月1日到12月31日的周数
<code>$lastyear=date('Y',strtotime($date))-1; $lastyearweeks=date('W',strtotime("31 December $lastyear"))-date('W',strtotime("1 September $lastyear"))+1;</code>
同样的,是否+1需要通过对9月1日是否为周六/日判断确定,这样,第六行就能替换成
<code>return (date('W', $timestamp)%53)+$lastyearweeks;</code>
同理,确定第二学期开学日期的话,类似思路修改最后一个retrun里的7,即可判断日期是第二学期的第几周
你们都被表面需求迷惑了,如果是问当前日期是开学日期的第几个月,楼主和一楼的逻辑虽然不完全对但是修改一下还是OK的,可是对于第几周就没必要了,因为问题的关键在于7天是一周。我的伪码如下
<code>$startDate = 开学日期; //如2016-02-16 $startDay = 开学这天是星期几; //如3表示周3 $limitDay = 今天是自1970年以来第几天 - 开学日期是自1970年以来的第几天; //比如55天 周日当每周的第一天了,此题中考虑这个问题没什么意义) $weekNumber = ceil(($limitDay + $startDay) / 7); //因为开学第一周可能不是整周,所以补上失去的天数</code>
$weekNumber就是你要的了
感谢大家的贡献. 我觉得可以从下面的表格作出分析(#注):
年份 | (春)上课日期 | (春)教学周数 | 暑假开始 | (秋)上课日期 | (秋)教学周数 | 寒假开始 | 除夕:周几 |
---|---|---|---|---|---|---|---|
2010 | 3/1 | 21 | 7/25 | 8/30 | 20 | 1/15 | 2/2:3 |
2011 | 2/21 | 18 | 6/25 | 8/29 | 20 | 1/15 | 1/22:7 |
2012 | 2/13 | 18 | 6/17 | 9/3 | 21 | 1/26 | 2/9:6 |
2013 | 2/25 | 18 | 6/29 | 9/2 | 20 | 1/18 | 1/30:4 |
2014 | 2/17 | 18 | 6/21 | 9/1 | 22 | 1/31 | 2/18:3 |
2015 | 3/2 | 18 | 7/4 | 8/31 | 21 | 1/23 | 2/8:1 |
2016 | 2/22 | 18 | 6/25 | 8/29 |
通过分析发现, 也许我们可以先分析什么时候过年, 然后暑假由过年前后各两周决定, 这里还需要些细化, 例如还和过年是星期几有关.
秋季开学由离9/1号最近的周一决定?
春季由开学日期(由过年决定)?
(#注: 统计结果可能不是非常正确, 大家可以复查.)
这东西还需要用算法做,或者算法能做出来么?直接把校历的时间录到数据库里就完了么
校历出一次管一年,也就是说1年录一次就可以,说白了,根本就没有规律,这个是教务处说了算的
真以为全国高校都9月1号开学 过年都让过元宵节啊 我在某985高校从来就没有在家过完元宵过

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