关于PHP读取时间号码有关问题

关于PHP读取时间号码问题

public function pai3(&$actionNo, &$actionTime, $time=null){<br />		$this->setTimeNo($actionTime, $time);<br />		//echo $actionTime,' ',date('Y-m-d H:i:s', $time);<br />		if($actionTime >= date('Y-m-d H:i:s', $time)){<br />			$actionNo = date('Yz', $time)-6;<br />		}else{<br />			$actionNo = date('Yz', $time)-6;<br />			$actionTime=date('Y-m-d 18:30', $time);<br />		}<br />	}

上面代码读取的年和号，如201456我想改成2014056增加一位，请问怎么改？
------解决方案--------------------

public function pai3(&$actionNo, &$actionTime, $time=null){<br />		$this->setTimeNo($actionTime, $time);<br />		//echo $actionTime,' ',date('Y-m-d H:i:s', $time);<br />		$year = date('Y', $time);<br />		$day = str_pad(date('z',$time),3,'0',STR_PAD_LEFT);<br />		$times = $year.$day;<br />		if($actionTime >= date('Y-m-d H:i:s', $time)){<br />			<br />			$actionNo = $times-6;<br />		}else{<br />			$actionNo = $times-6;<br />			$actionTime=date('Y-m-d 18:30', $time);<br />		}<br />	}