php【数组对比输出】解决办法

php【数组对比输出】

<br />$array1=array("1","2","3","4","5","6");//此数据值固定。<br />$array2=array("1","3","6","4");//此数据值不固定。<br />

实现效果：
array2与array1对比后array2没有的值用0代替。
结果：
1,0,3,4,0,6

请问怎么实现
------解决思路----------------------

<br />$arr = array();<br />$x;<br />foreach($array2 as $k => $v) {<br />    x = array_search($v,$array1);<br />     if (x) {<br />        $arr[$k] = $v;<br />    } else {<br />        $arr[$k] = 0;<br />    }<br />}<br />

------解决思路----------------------

$array1=array("1","2","3","4","5","6");//此数据值固定。<br />$array2=array("1","3","6","4");//此数据值不固定。<br />$arr = array();<br />foreach($array1 as $v){<br /> $arr[] = in_array($v, $array2) ? $v : 0;<br />}<br />print_r($arr);

------解决思路----------------------

引用

#1
$arr = array();
$x;
foreach($array2 as $k => $v) {
x = array_search($v,$array1);
if (x) {
$arr[$k] = $v;
} else {
$arr[$k] = 0;
}
}

array_search()返回的是匹配到的键名，当第一个匹配到，键名是0，if判断就不存在了，这里存在一点问题
------解决思路----------------------
php里面有个数组比较函数 array_diff的呀。
------解决思路----------------------
不错，可以借助 array_diff

$a = array("1","2","3","4","5","6");<br />$b = array("1","3","6","4");<br />$c = $a;<br />foreach(array_diff($a, $b) as $k=>$v) $c[$k] = 0;<br /><br />print_r($c);

Array<br />(<br />    [0] => 1<br />    [1] => 0<br />    [2] => 3<br />    [3] => 4<br />    [4] => 0<br />    [5] => 6<br />)<br /><br />

------解决思路----------------------

<br />$array1=array("1","2","3","4","5","6");//此数据值固定。<br />$array2=array("1","3","6","4");//此数据值不固定。<br /><br>$c = array_diff($array1, $array2);<br><br>foreach($c as $k=>$v){<br>    $array1[$k] = 0;<br>}<br><br>print_r($array1);<br>

Array
(
    [0] => 1
    [1] => 0
    [2] => 3
    [3] => 4
    [4] => 0
    [5] => 6
)