一段下传图片，并在MYSQL中记录路径的代码求指正

一段上传图片，并在MYSQL中记录路径的代码求指正
只上传一张图片的功能已经实现，上传两张图片就实现不了，代码段比较简单，麻烦大家指导一下：

上传图片的表单：

PHP code

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<?php if ( isset($_GET['action']) && $_GET['action'] == "save" )
{
include_once('conn.php');  //连接数据库
include_once('uploadclass.php');//这个文件在下文会给出

$pic=$uploadfile;   //第一张图片，已经可以正常上传
$pic2=$uploadfile2; //第二张，上传不了

$sql="insert into product (pic,pic2) values ('$pic','$pic2')";
$result=mysql_query($sql,$conn);
if   (!$result)
{
      echo mysql_error();
      echo $sql;
      exit;
}
else
{
      echo"<Script>window.alert('congratulations,the product data inserted successful');location.href='index.php'";
} 

mysql_close();
}

?>



<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Administrator for upload the product resource</title>

Images_1:
Images_2:

上传程序：uploadclass.php（此程序只能上传图片1，如果要能上传图片2，需要怎么加代码呢？）

PHP code

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<?php $uploaddir = "../images/upfiles/";
$type=array("jpg","gif","bmp","jpeg","png");
$patch="aloesky/";

function fileext($filename)
{
return substr(strrchr($filename, '.'), 1);
}

function random($length)
{
$hash = 'CR-';
$chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz';
$max = strlen($chars) - 1;
mt_srand((double)microtime() * 1000000);
for($i = 0; $i < $length; $i++)
{
$hash .= $chars[mt_rand(0, $max)];
}
return $hash;
}

$a=strtolower(fileext($_FILES['file']['name']));
if(!in_array(strtolower(fileext($_FILES['file']['name'])),$type))
{
$text=implode(",",$type);
echo "You can only upload the following types of files:",$text,"<br /> <a href="upload_pro.php">return and try again?click me</a>";
exit;
}
else{
$filename=explode(".",$_FILES['file']['name']);
do
{
$filename[0]=random(10); 
$name=implode(".",$filename);
//$name1=$name.".Mcncc";
$uploadfile=$uploaddir.$name;
}

while(file_exists($uploadfile));

if (move_uploaded_file($_FILES['file']['tmp_name'],$uploadfile))
{
if(is_uploaded_file($_FILES['file']['tmp_name']))
{

echo "the Images Upload failed!";
}
else
{
echo "<center>Your file has been uploaded: </center><br><center><img  src="%24uploadfile" alt=" 一段下传图片，并在MYSQL中记录路径的代码求指正 " ></center>";
echo "<br><center><a href="upload_pro.php">Continue to upload</a></center>";
}
}
}
?>

 

------解决方案--------------------

探讨

引用:


这样当成数组就好处理了。
php端： print_r($_FILES['file']); //得到一个二维数组，只需处理数组即可.