php如何$_G两个数据表里的不同数据?

WBOY
Libérer: 2016-09-30 09:37:34
original
1477 Les gens l'ont consulté

这是原来的调用:
$_G['db']->from('dbpre_subject');
$_G['db']->select('*');
$_G['db']->where('city_id', array(0,$_CITY['aid']));
$_G['db']->where_concat_like('name,subname', "%{$q}%");
$_G['db']->where('status', 1);

现在我要在此基础之上,在调用dbpre_subject_product_new 这个数据表里的c_product_price和c_product_content这两个字段,,,改怎么写,,,先谢谢诸位大神了

//把源码贴上

!defined('IN_MUDDER') && exit('Access Denied');

$city_id = _get('city_id', null, MF_INT_KEY);
if($city_id>0) {

<code>$citys = $_G['loader']->variable('area');
if(!$city = $citys[$city_id]) redirect('global_area_city_id_invalid');
if(!$city['enabled']) redirect('global_area_city_disabled');
init_city($city_id);</code>
Copier après la connexion
Copier après la connexion

}

$q = _input('keyword', '', MF_TEXT);
if(($_GET['Pathinfo'] || $_GET['Rewrite']) && $q && $_G['charset'] != 'utf-8' && $_G'cfg') {

<code>$q = charset_convert($q,'utf-8',$_G['charset']);</code>
Copier après la connexion
Copier après la connexion

}
$q = str_replace(array("rn","r","n") ,'', _T($q));

$_G['db']->from('dbpre_subject');
$_G['db']->select('*');
$_G['db']->where('city_id', array(0,$_CITY['aid']));
$_G['db']->where_concat_like('name,subname', "%{$q}%");
$_G['db']->where('status', 1);

$multipage = '';
if($total = $_G['db']->count()) {

<code>$_G['db']->sql_roll_back('from,select,where');
$orderby = array($post['ordersort']=>$post['ordertype']);
$offset = 10;
$start = get_start($_GET['page'], $offset);
$_G['db']->order_by($orderby);
$_G['db']->limit($start, $offset);
$list = $_G['db']->get();
if($total) {
    $multipage = mobile_page($total, $offset, $_GET['page'], url("item/mobile/do/search/keyword/$q/page/_PAGE_"));
}</code>
Copier après la connexion
Copier après la connexion

}

//显示模版
if($_G['in_ajax']) {

<code>include mobile_template('item_list_li');
output();</code>
Copier après la connexion
Copier après la connexion

}

$title = '搜索产品:'.$q;
include mobile_template('item_list');

回复内容:

这是原来的调用:
$_G['db']->from('dbpre_subject');
$_G['db']->select('*');
$_G['db']->where('city_id', array(0,$_CITY['aid']));
$_G['db']->where_concat_like('name,subname', "%{$q}%");
$_G['db']->where('status', 1);

现在我要在此基础之上,在调用dbpre_subject_product_new 这个数据表里的c_product_price和c_product_content这两个字段,,,改怎么写,,,先谢谢诸位大神了

//把源码贴上

!defined('IN_MUDDER') && exit('Access Denied');

$city_id = _get('city_id', null, MF_INT_KEY);
if($city_id>0) {

<code>$citys = $_G['loader']->variable('area');
if(!$city = $citys[$city_id]) redirect('global_area_city_id_invalid');
if(!$city['enabled']) redirect('global_area_city_disabled');
init_city($city_id);</code>
Copier après la connexion
Copier après la connexion

}

$q = _input('keyword', '', MF_TEXT);
if(($_GET['Pathinfo'] || $_GET['Rewrite']) && $q && $_G['charset'] != 'utf-8' && $_G'cfg') {

<code>$q = charset_convert($q,'utf-8',$_G['charset']);</code>
Copier après la connexion
Copier après la connexion

}
$q = str_replace(array("rn","r","n") ,'', _T($q));

$_G['db']->from('dbpre_subject');
$_G['db']->select('*');
$_G['db']->where('city_id', array(0,$_CITY['aid']));
$_G['db']->where_concat_like('name,subname', "%{$q}%");
$_G['db']->where('status', 1);

$multipage = '';
if($total = $_G['db']->count()) {

<code>$_G['db']->sql_roll_back('from,select,where');
$orderby = array($post['ordersort']=>$post['ordertype']);
$offset = 10;
$start = get_start($_GET['page'], $offset);
$_G['db']->order_by($orderby);
$_G['db']->limit($start, $offset);
$list = $_G['db']->get();
if($total) {
    $multipage = mobile_page($total, $offset, $_GET['page'], url("item/mobile/do/search/keyword/$q/page/_PAGE_"));
}</code>
Copier après la connexion
Copier après la connexion

}

//显示模版
if($_G['in_ajax']) {

<code>include mobile_template('item_list_li');
output();</code>
Copier après la connexion
Copier après la connexion

}

$title = '搜索产品:'.$q;
include mobile_template('item_list');

你这是什么框架呢?不同的框架有不同的语法

Étiquettes associées:
php
source:php.cn
Déclaration de ce site Web
Le contenu de cet article est volontairement contribué par les internautes et les droits d'auteur appartiennent à l'auteur original. Ce site n'assume aucune responsabilité légale correspondante. Si vous trouvez un contenu suspecté de plagiat ou de contrefaçon, veuillez contacter admin@php.cn
Tutoriels populaires
Plus>
Derniers téléchargements
Plus>
effets Web
Code source du site Web
Matériel du site Web
Modèle frontal