复制代码 代码如下:
//----显示上一篇、下一篇文章代码 START----
$sql_former = "select * from article where id$sql_later = "select * from article where id>$id "; //下一篇文章sql语句
$queryset_former = mysql_query($sql_former); //执行sql语句
if(mysql_num_rows($queryset_former)){ //返回记录数,并判断是否为真,以此为依据显示结果
$result = mysql_fetch_array($queryset_former);
echo "上一篇
". $result[title]." ";
} else {echo "上一篇 没有了
";}
$queryset_later = mysql_query($sql_later);
if(mysql_num_rows($queryset_later)){
$result = mysql_fetch_array($queryset_later);
echo "下一篇
". $result['title']."";
} else {echo "下一篇 没有了
";}
?>