PHPの配列内のキー値が空の場合、配列に追加されません

PHP の配列内のキー値が空の場合、そのキー値は配列に追加されません。

<br />	$data = array();<br />			if (!empty($_POST['field_id'])) {<br />				foreach ($_POST['field_id'] as $k => $v) {<br />					$data[] = array(<br />						'field_id' => $v, <br />						'choice' => isset($_POST['choice'][$k]) ? $_POST['choice'][$k] : '', <br />						'uid' => $_POST['uid'],<br />						'game_id' => $_POST['game_id'],<br />						'server_id' => $_POST['server_id']<br />					);  <br />				}   <br />			}  <br />

ここでフォーマットをループします。以下は出力配列データです

<br />Array<br />(<br />    [0] => Array<br />        (<br />            [field_id] => 1<br />            [choice] => 0<br />            [uid] => 110000110<br />            [game_id] => 2<br />            [server_id] => 2<br />        )<br /><br />    [1] => Array<br />        (<br />            [field_id] => 2<br />            [choice] => 0<br />            [uid] => 110000110<br />            [game_id] => 2<br />            [server_id] => 2<br />        )<br /><br />    [2] => Array<br />        (<br />            [field_id] => 3<br />            [choice] => 1<br />            [uid] => 110000110<br />            [game_id] => 2<br />            [server_id] => 2<br />        )<br /><br />)<br /><br />

choice が空の [choice] => 値なしの場合データ配列に追加せずにこれを実現できますか?

-----ソリューションのアイデア----------------------

$data = array();<br />if (!empty($_POST['field_id'])) {<br />   foreach ($_POST['choice'] as $k => $v) {<br />      if($v == '') continue;<br />      $data[] = array(<br />          'field_id' => $_POST['field_id'][$k], <br />          'choice' => $_POST['choice'][$k], <br />          'uid' => $_POST['uid'],<br />          'game_id' => $_POST['game_id'],<br />          'server_id' => $_POST['server_id']<br />      );  <br />  }   <br />}