判定は指定値出力を参照！

<?php$n=$_GET['che'];define("A", $n);if(A==star){echo '1';}else if(A==movie){echo '9';}else if(A==tv){echo '10';}else if(A==yue){echo '10';}else if(A==zongyi){echo '12';}else if(A==news){echo '15';}else if(A==yanchu){echo '13';}else if(A==fashion){echo '20';}else if(A==astro){echo '23';}在这里弄个  统一的值输出$b  这样 echo 里的值全弄到$b去  用B输出?>

ディスカッションへの返信 (解決策)

$n=$_GET['che'];define("A", $n);$b = '';if(A=='star'){$b = '1';}else if(A=='movie'){$b = '9';}else if(A=='tv'){$b = '10';}else if(A=='yue'){$b = '10';}else if(A=='zongyi'){$b = '12';}else if(A=='news'){$b = '15';}else if(A=='yanchu'){$b = '13';}else if(A=='fashion'){$b = '20';}else if(A=='astro'){$b = '23';}echo $b;

$dict = array(  'star' => '1',  'movie' => '9',  'tv' => '10',  'yue' => '10',  'zongyi' => '12',  'news' => '15',  'yanchu' => '13',  'fashion' => '20',  'astro' => '23',);echo isset($dict[$_GET['che']]) ? $dict[$_GET['che']] : ''

$dict = array(  'star' => '1',  'movie' => '9',  'tv' => '10',  'yue' => '10',  'zongyi' => '12',  'news' => '15',  'yanchu' => '13',  'fashion' => '20',  'astro' => '23',);echo isset($dict[$_GET['che']]) ? $dict[$_GET['che']] : ''

兄弟