PHP を使用してバックアップ データベースの ZIP とエクスポートを実装する

 经常在有的PHP开源系统中，看到有备份数据库并导出的方法，其实代码不复杂，下面 
大概讲解下，以WINDOWS为例子，两类方法，一个是目录文件夹要有执行脚本权限的， 
一个个是没有权限的，代码如下： 

一） 

<?php   
    
$username = "root";    
$password = "";    
$hostname = "localhost";    
$dbname   = "test";   
    
  
$dumpfname = $dbname . "_" . date("Y-m-d_H-i-s").".sql";   
$command = "C:\\xampp\\mysql\\bin\\mysqldump --add-drop-table --host=$hostname   
    --user=$username ";   
if ($password)    
        $command.= "--password=". $password ." ";    
$command.= $dbname;   
$command.= " > " . $dumpfname;   
system($command);   
    
// zip 数据文件  
$zipfname = $dbname . "_" . date("Y-m-d_H-i-s").".zip";   
$zip = new ZipArchive();   
if($zip->open($zipfname,ZIPARCHIVE::CREATE))    
{   
   $zip->addFile($dumpfname,$dumpfname);   
   $zip->close();   
}   
    
// read zip file and send it to standard output   
if (file_exists($zipfname)) {   
    header(&#39;Content-Description: File Transfer&#39;);   
    header(&#39;Content-Type: application/octet-stream&#39;);   
    header(&#39;Content-Disposition: attachment; filename=&#39;.basename($zipfname));   
    flush();   
    readfile($zipfname);   
    exit;   
}   
?>

方法2 文件夹没相关权限

<?php   
ob_start();   
    
$username = "root";    
$password = "";    
$hostname = "localhost";    
$dbname   = "test";   
    
$command = "C:\\xampp\\mysql\\bin\\mysqldump --add-drop-table --host=$hostname   
    --user=$username ";   
if ($password)    
        $command.= "--password=". $password ." ";    
$command.= $dbname;   
system($command);   
    
$dump = ob_get_contents();    
ob_end_clean();   
    
  
//不ZIP了  
header(&#39;Content-Description: File Transfer&#39;);   
header(&#39;Content-Type: application/octet-stream&#39;);   
header(&#39;Content-Disposition: attachment; filename=&#39;.basename($dbname . "_" .    
    date("Y-m-d_H-i-s").".sql"));   
flush();   
echo $dump;   
exit();]]>   
?>