javascript - PHP和Ajax做的分页跳转,可是出不来。望大神能看看

Question

想做一个ajax局部刷新分页跳转，可是不知道为什么用ajax接受的数据在页面
上显示出来总是这么一句话MySql ErrorNo database selected 然后我做了几个测试
发现echo"111111";echo"22222";echo"3333"echo"4444";只有4444输出！PHP我不是很懂
所以想麻烦大神们看下是怎么回事！小弟在此谢过了！

---

<meta http-equiv="Content-Type" content="text/html; charset=utf8" />
<?php
if($_REQUEST['page'])
{
    $page = $_REQUEST['page'];
    $page=1;
    $cur_page = $page;
    $page -= 1;
    $per_page = 10;
    $previous_btn = true;
    $next_btn = true;
    $first_btn = true;
    $last_btn = true;
    $start = $page * $per_page;


    $conn=mysqli_connect("localhost","root","","info");
    mysqli_query($conn,"SET NAMES 'utf8'");
    **echo "44444444";**
    $query_pag_data = "SELECT id,name from content LIMIT $start, $per_page";
    $result_pag_data = mysql_query($query_pag_data) or die('MySql Error' . mysql_error());
    $msg = "";
    while ($row = mysql_fetch_array($result_pag_data)) {
        $htmlmsg=htmlspecialchars($row['name']);
        $msg .= "<li><b>" . $row['id'] . "</b> " . $htmlmsg . "</li>";
    }
    $msg = "<p class='data'><ul>" . $msg . "</ul></p>"; // Content for Data

    **echo "3333333333333333333333";**
    /* --------------------------------------------- */
    $query_pag_num = "SELECT COUNT(*) AS count FROM content";
    $result_pag_num = mysql_query($query_pag_num);
    $row = mysql_fetch_array($result_pag_num);
    $count = $row['count'];
    $no_of_paginations = ceil($count / $per_page);

    **echo "2222222222";**

    /* ---------------Calculating the starting and endign values for the loop----------------------------------- */
    if ($cur_page >= 7) {
        $start_loop = $cur_page - 3;
        if ($no_of_paginations > $cur_page + 3)
            $end_loop = $cur_page + 3;
        else if ($cur_page <= $no_of_paginations && $cur_page > $no_of_paginations - 6) {
            $start_loop = $no_of_paginations - 6;
            $end_loop = $no_of_paginations;
        } else {
            $end_loop = $no_of_paginations;
        }
    } else {
        $start_loop = 1;
        if ($no_of_paginations > 7)
            $end_loop = 7;
        else
            $end_loop = $no_of_paginations;
    }
    /* ----------------------------------------------------------------------------------------------------------- */
    $msg .= "<p class='pagination'><ul>";

    // FOR ENABLING THE FIRST BUTTON
    if ($first_btn && $cur_page > 1) {
        $msg .= "<li p='1' class='active'>First</li>";
    } else if ($first_btn) {
        $msg .= "<li p='1' class='inactive'>First</li>";
    }

    // FOR ENABLING THE PREVIOUS BUTTON
    if ($previous_btn && $cur_page > 1) {
        $pre = $cur_page - 1;
        $msg .= "<li p='$pre' class='active'>Previous</li>";
    } else if ($previous_btn) {
        $msg .= "<li class='inactive'>Previous</li>";
    }
    for ($i = $start_loop; $i <= $end_loop; $i++) {

        if ($cur_page == $i)
            $msg .= "<li p='$i' style='color:#fff;background-color:#006699;' class='active'>{$i}</li>";
        else
            $msg .= "<li p='$i' class='active'>{$i}</li>";
    }

    // TO ENABLE THE NEXT BUTTON
    if ($next_btn && $cur_page < $no_of_paginations) {
        $nex = $cur_page + 1;
        $msg .= "<li p='$nex' class='active'>Next</li>";
    } else if ($next_btn) {
        $msg .= "<li class='inactive'>Next</li>";
    }

    // TO ENABLE THE END BUTTON
    if ($last_btn && $cur_page < $no_of_paginations) {
        $msg .= "<li p='$no_of_paginations' class='active'>Last</li>";
    } else if ($last_btn) {
        $msg .= "<li p='$no_of_paginations' class='inactive'>Last</li>";
    }
    $goto = "<input type='text' class='goto' size='1' style='margin-top:-1px;margin-left:60px;'/><input type='button' id='go_btn' class='go_button' value='Go'/>";
    $total_string = "<span class='total' a='$no_of_paginations'>Page <b>" . $cur_page . "</b> of <b>$no_of_paginations</b></span>";
    $msg = $msg . "</ul>" . $goto . $total_string . "</p>";  // Content for pagination
    **echo $msg;**
    **echo "1111111111111";**
}
?>

以上是代码

Answer 1

看一下文档啊 少年 点击链接
既然你是用的mysqli，三楼说的没错，选择一下数据库，mysqli是mysqli_select_db()这个，链接里有，你看下。

Answer 2

mysql 和mysqli混用！
上面用的$conn=mysqli_connect("localhost","root","","info");
下面用mysql_query($query_pag_data)

要不改成

$conn=mysql_connect("localhost","root","","info");
mysql_query($conn,"SET NAMES 'utf8'");

Answer 3

这个报错是因为没有选择数据库呀，你在连接之后执行一下mysqli_query('use database')，database是你的数据库，另外像楼上说的，别mysqli和mysql混杂用，php官方已经放弃mysql扩展了，用pdo或者mysqli