android - bindservice 执行ondestroy后有没有被销毁

Question

在mainActivity中我调用了unbindservice，并且在log中看到执行了bindservice的oddestroy函数，这样应该是销毁了service，但是我在mainActivity中再调用binder.getthis还能输出bindservice的this.tostring。这又表明service还存在
这是怎么回事

这是bindservice的定义
public class BindService extends Service {

private int count=0;
private boolean quit=false;
private String LOG_TAG="--BindService--";
private MyBinder binder=new MyBinder();

public class  MyBinder extends Binder{
    public int getCount()
    {
        return count;
    }
    public boolean getQuit()
    {
        return quit;
    }
    public String getthis()
    {
        return test();
    }
}
@Override
public IBinder onBind(Intent intent)//?这里的intent 有什么用
{
    Log.w(LOG_TAG,"onBind");
    return  binder;
}
@Override
public  void onCreate()
{
    super.onCreate();
    Log.w(LOG_TAG,"on Created");
    new Thread(){
        @Override
        public void run()
        {
            while (!quit)
            {
                try {
                    Thread.sleep(1000);
                }catch (InterruptedException e)
                {}
                count ++;
            }
        }
    }.start();
}
@Override
public boolean onUnbind(Intent intent)
{
    this.quit=true;
    Log.w(LOG_TAG,"Unbind");
    return  true;
}

@Override
public  void  onDestroy()
{
    super.onDestroy();
    Log.w(LOG_TAG,"Destroy");
    this.quit=true;
}
public String test(){
    return this.toString();
}

}

activity 代码：

public class BindServiceActivity extends AppCompatActivity {

private String LOG_TAG="--connection--";
BindService.MyBinder binder;
Intent intent;
myConn conn=new myConn();

class myConn implements ServiceConnection {
    private boolean actived=false;
    @Override
    public void onServiceConnected(ComponentName name, IBinder service) {
        actived=true;
        Log.w(LOG_TAG,"Connected");
        binder=(BindService.MyBinder)service;
    }
    @Override
    public void onServiceDisconnected(ComponentName name)
    {
        actived=false;
        Log.w(LOG_TAG,"Disconnected");
    }
    public boolean isActived()
    {
        return actived;
    }
}

@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.bindservice);
    intent=new Intent(this,BindService.class);
}
public void myBind(View view)
{
    Log.w(LOG_TAG,"bind clicked");
    bindService(intent,conn, Service.BIND_AUTO_CREATE);
}
public  void myUnBind(View view)
{
  //  Log.w(LOG_TAG,binder.toString());
    if(conn.isActived())
    {
        if (!binder.getQuit())
        {
            //这里仅仅是解除conn 与 service 之间的关系，binder 并没有被销毁，因此还能调用getcount
            unbindService(conn);
        } else
        {
            Toast.makeText(this, "Conn is already disconnected", Toast.LENGTH_SHORT).show();
        }
    }else
    {
        Toast.makeText(this, "Conn ia not connected", Toast.LENGTH_SHORT).show();
    }
}
public void myShowStatus(View view) {
    if (conn.isActived()) {
        Log.w(LOG_TAG,binder.getthis());
        TextView txt=(TextView)findViewById(R.id.txt);
        txt.setText("Count of service is:" + binder.getCount());
        //Toast.makeText(this, "Count of service is:" + binder.getCount(), Toast.LENGTH_SHORT).show();
    }else {
        Toast.makeText(this, "Conn ia not connected", Toast.LENGTH_SHORT).show();
    }
}
public void myBack(View s)
{
    finish();
}

}

Answer 1

BindService の内部クラス MyBinder は、外部クラス BindService のインスタンスを保持します