Prototype and prototype chain are one of the high-frequency front-end interview questions. I believe many friends have encountered this problem. So do you understand it clearly and completely?
[Related recommendations: Front-end interview questions]
International practice, let us first ask the question:
Maybe you already have the answer, Maybe you are starting to have some doubts, whether it is get
a new skill or a simple review, let us explore it together
If there are any flaws or errors in the article, please let us know. Please give me some advice if you see it, thank you in advance
JavaScript
is based on prototypeEvery function we create has a
prototype(Prototype)
Attribute, this attribute is a pointer to an object, and the purpose of this object is to contain properties and methods that can be shared by all instances of a specific type.
To put it simply, when we create a function, the system will automatically assign a prototype
attribute, which can be used to store attributes and methods that can be shared by all instances.
It will be clearer if you use a picture:
##Illustration:
attribute, which points to an object, that is, the prototype object
attribute by default, which points to Its constructor
, pointing to its prototype object
function Person(){} var p = new Person(); p.__proto__ === Person.prototype // true Person.prototype.constructor === Person // true
function Person(){} Person.prototype.name = 'tt'; Person.prototype.age = 18; Person.prototype.sayHi = function() { alert('Hi'); } var person1 = new Person(); var person2 = new Person(); person1.name = 'oo'; person1.name // oo person1.age // 18 perosn1.sayHi() // Hi person2.age // 18 person2.sayHi() // Hi
function Person() {} Person.prototype = { name: 'tt', age: 18, sayHi() { console.log('Hi'); } } var p = new Person()
function Person(){} var p = new Person(); Person.prototype = { name: 'tt', age: 18 } Person.prototype.constructor === Person // false p.name // undefined
property of the prototype object to point to
Object, causing confusion in the prototype chain relationship. Therefore, we should specify
constructor(
when rewriting the prototype object. instanceof will still return the correct value)
Person.prototype = { constructor: Person }
constructor property in this way will cause its
Enumerable attribute to be Set to
true (default is
false)
prototype (prototype) and its characteristics, then the prototype What is a chain?
All objects in JavaScript are inherited from its prototype object. The prototype object itself is also an object, and it also has its own prototype object. In this way, a structure similar to a linked list is formed, which is the prototype chain
Similarly, we use a picture to describe attribute of the
Object function
The prototype object pointed to also has a prototype, but its prototype is
null, while
null has no prototype
p instance attribute. If this attribute does not exist in itself or in the prototype chain, Then the final value of the attribute is
undefined. If it is a method, an error will be thrown.
ES6Why isprovides
Class( Class)This concept, as the template of the object, can define the class through the
classkeyword
class mentioned:
## The
of #ES6
can be regarded as just a syntactic sugar. Most of its functions can be achieved by ES5
. The new class
The writing method just makes the writing method of object prototype clearer and more like the syntax of object-oriented programming<div class="code" style="position:relative; padding:0px; margin:0px;"><pre class="brush:js;toolbar:false;">class Point {
constructor(x, y) {
this.x = x;
this.y = y;
}
toString() {
return &#39;(&#39; + this.x + &#39;, &#39; + this.y + &#39;)&#39;;
}
}
// 可以这么改写
function Point(x, y) {
this.x = x;
this.y = y;
}
Point.prototype.toString = function () {
return &#39;(&#39; + this.x + &#39;, &#39; + this.y + &#39;)&#39;;
};</pre><div class="contentsignin">Copy after login</div></div><p><code>class
里面定义的方法,其实都是定义在构造函数的原型上面实现实例共享,属性定义在构造函数中,所以 ES6
中的类完全可以看作构造函数的另一种写法
除去 class
类中的一些行为可能与 ES5
存在一些不同,本质上都是通过原型、原型链去定义方法、实现共享。所以,还是文章开始那句话 JavaScript是基于原型的
更多 class
问题,参考这里
instanceof
最常用的确定原型指向关系的关键字,检测的是原型,但是只能用来判断两个对象是否属于实例关系, 而不能判断一个对象实例具体属于哪种类型
function Person(){} var p = new Person(); p instanceof Person // true p instanceof Object // true
hasOwnProperty
通过使用 hasOwnProperty
可以确定访问的属性是来自于实例还是原型对象
function Person() {} Person.prototype = { name: 'tt' } var p = new Person(); p.age = 15; p.hasOwnProperty('age') // true p.hasOwnProperty('name') // false
由于原型链的存在,我们可以让很多实例去共享原型上面的方法和属性,方便了我们的很多操作。但是原型链并非是十分完美的
function Person(){} Person.prototype.arr = [1, 2, 3, 4]; var person1 = new Person(); var person2 = new Person(); person1.arr.push(5) person2.arr // [1, 2, 3, 4, 5]
引用类型,变量保存的就是一个内存中的一个指针。所以,当原型上面的属性是一个引用类型的值时,我们通过其中某一个实例对原型属性的更改,结果会反映在所有实例上面,这也是原型 共享
属性造成的最大问题
另一个问题就是我们在创建子类型(比如上面的 p
)时,没有办法向超类型( Person
)的构造函数中传递参数
The above is the detailed content of JS interview frequently asked questions Prototype and prototype chain. For more information, please follow other related articles on the PHP Chinese website!