단일 MySQL 테이블에 빈 행이 있는 지난 7일간의 트랜잭션을 검색하는 방법은 무엇입니까?

지난 7일간의 거래를 검색하고 MySQL 단일 테이블에 빈 행 포함

지난 7일간의 거래를 추출하는 문제를 해결하려면 MySQL 데이터베이스에서 빈 행을 캡처하여 다음을 탐색합니다. 접근 방식:

1. 날짜 범위 생성:
   다음 쿼리를 사용하여 지난 7일 동안의 날짜 목록을 만드는 것으로 시작합니다.

   select DATE_FORMAT(a.Date,'%Y-%m-%d') as purchase_date,
   '0' as  amount
   from (
      select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
      from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
      cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
      cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
   ) a
   where a.Date BETWEEN NOW() - INTERVAL 7 DAY AND NOW()

2. 거래 참여 테이블:
   다음으로 생성된 날짜 목록을 거래 테이블과 결합하여 해당 판매 금액을 얻습니다(있는 경우).

   SELECT t1.purchase_date,
   coalesce(SUM(t1.amount+t2.amount), 0) AS amount
   from

   (
     select DATE_FORMAT(a.Date,'%Y-%m-%d') as purchase_date,
     '0' as  amount
     from (
        select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
        from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
        cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
        cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
     ) a
     where a.Date BETWEEN NOW() - INTERVAL 7 DAY AND NOW()
   )t1
   left join

   (
     SELECT DATE_FORMAT(purchase_date, '%Y-%m-%d') as purchase_date,
     coalesce(SUM(amount), 0) AS amount
     FROM transactions
     WHERE purchase_date BETWEEN NOW() - INTERVAL 7 DAY AND NOW()
     AND vendor_id = 0
     GROUP BY purchase_date
   )t2
   on t2.purchase_date = t1.purchase_date
   group by t1.purchase_date
   order by t1.purchase_date desc

전체 쿼리:

select
t1.purchase_date,
coalesce(SUM(t1.amount+t2.amount), 0) AS amount
from
(
  select DATE_FORMAT(a.Date,'%Y-%m-%d') as purchase_date,
  '0' as  amount
  from (
    select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
    from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
    cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
  ) a
  where a.Date BETWEEN NOW() - INTERVAL 7 DAY AND NOW()
)t1
left join
(
  SELECT DATE_FORMAT(purchase_date, '%Y-%m-%d') as purchase_date,
  coalesce(SUM(amount), 0) AS amount
  FROM transactions
  WHERE purchase_date BETWEEN NOW() - INTERVAL 7 DAY AND NOW()
  AND vendor_id = 0
  GROUP BY purchase_date
)t2
on t2.purchase_date = t1.purchase_date
group by t1.purchase_date
order by t1.purchase_date desc

이 포괄적인 쿼리를 활용하여 쿼리를 사용하면 거래가 없는 날에 대한 빈 행을 포함하여 지난 7일 동안의 총 매출을 효과적으로 추출할 수 있습니다.

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