SQL의 상위 및 하위 테이블에 데이터를 효율적으로 삽입하는 방법은 무엇입니까?

SQL 상위-하위 테이블 데이터를 효율적으로 삽입

이 글에서는 SQL 상위-하위 테이블에 데이터를 효율적으로 삽입하는 방법을 소개합니다.

1. UDT에 EmployeeId 열을 추가합니다

<code class="language-sql">CREATE TYPE dbo.tEmployeeData AS TABLE (
    FirstName NVARCHAR(50),
    LastName NVARCHAR(50),
    DepartmentType NVARCHAR(10),
    DepartmentBuilding NVARCHAR(50),
    DepartmentEmployeeLevel NVARCHAR(10),
    DepartmentTypeAMetadata NVARCHAR(100),
    DepartmentTypeBMetadata NVARCHAR(100),
    EmployeeId INT
);
GO</code>

2. EmployeeId 열을 채웁니다.

<code class="language-sql">DECLARE @tEmployeeData dbo.tEmployeeData;
INSERT INTO @tEmployeeData (FirstName, LastName, DepartmentType, DepartmentBuilding, DepartmentEmployeeLevel, DepartmentTypeAMetadata, DepartmentTypeBMetadata, EmployeeId)
SELECT N'Tom_FN', N'Tom_LN', N'A', N'101', N'IV', N'Tech/IT', NULL, 5
UNION
SELECT N'Mike_FN', N'Mike_LN', N'B', N'OpenH', N'XII', NULL, N'Med', 6
UNION
SELECT N'Joe_FN', N'Joe_LN', N'A', N'101', N'IV', N'Tech/IT', NULL, 7
UNION
SELECT N'Dave_FN', N'Dave_LN', N'B', N'OpenC', N'XII', NULL, N'Lab', 8;</code>

3. MERGE 문을 사용하여 Employee 테이블을 채웁니다.

<code class="language-sql">DECLARE @EmployeeidMap TABLE (temp_id INT, id INT);
MERGE INTO @MainEmployee AS target
USING @tEmployeeData AS sourceData ON 1 = 0
WHEN NOT MATCHED THEN
    INSERT (FirstName, LastName)
    VALUES (sourceData.FirstName, sourceData.LastName)
OUTPUT sourceData.EmployeeId, inserted.EmployeeID
INTO @EmployeeidMap (temp_id, id);</code>

4. ParentEmployeeDepartment 테이블 채우기

<code class="language-sql">INSERT INTO @ParentEmployeeDepartment (EmployeeID, DepartmentType)
SELECT Id, DepartmentType
FROM @tEmployeeData
INNER JOIN @EmployeeidMap ON EmployeeID = temp_id;</code>

5. ChildEmployeeDepartmentTypeA 및 ChildEmployeeDepartmentTypeB 테이블을 채웁니다.

<code class="language-sql">INSERT INTO @ChildEmployeeDepartmentTypeA (ParentEmployeeDepartmentID, DepartmentBuilding, DepartmentEmployeeLevel, DepartmentTypeAMetadata)
SELECT ParentEmployeeDepartmentID, DepartmentBuilding, DepartmentEmployeeLevel, DepartmentTypeAMetadata
FROM @tEmployeeData
INNER JOIN @EmployeeidMap ON EmployeeID = temp_id
WHERE DepartmentType = 'A';

INSERT INTO @ChildEmployeeDepartmentTypeB (ParentEmployeeDepartmentID, DepartmentBuilding, DepartmentEmployeeLevel, DepartmentTypeBMetadata)
SELECT ParentEmployeeDepartmentID, DepartmentBuilding, DepartmentEmployeeLevel, DepartmentTypeBMetadata
FROM @tEmployeeData
INNER JOIN @EmployeeidMap ON EmployeeID = temp_id
WHERE DepartmentType = 'B';</code>

6. 결과 출력

<code class="language-sql">SELECT * FROM @MainEmployee;
SELECT * FROM @ParentEmployeeDepartment;
SELECT * FROM @ChildEmployeeDepartmentTypeA;
SELECT * FROM @ChildEmployeeDepartmentTypeB;</code>

위 내용은 SQL의 상위 및 하위 테이블에 데이터를 효율적으로 삽입하는 방법은 무엇입니까?의 상세 내용입니다. 자세한 내용은 PHP 중국어 웹사이트의 기타 관련 기사를 참조하세요!