javascript和html之间的交互问题，求高手解答
javascript 怎么通知php处理数据，然后返回结果，javascript继续处理，然后html显示？
------解决方案--------------------
<html><br /><head><br /><title></title><br /><script type="text/javascript" src="http://code.jquery.com/jquery-1.10.2.min.js"></script><br /><script type="text/javascript"><br />function click2()<br />{<br />alert("wwww");<br />$.ajax({<br /> type: "GET",<br /> url: "del.php",<br /> data: "num=3",<br /> success: function(msg){<br /> alert( "Data Saved: " + msg );<br /> //成功html显示结果<br /> }<br />});<br />}<br /></script><br /></head><br /><body><br /><input type="button" onclick="click2()" value="test"><br /></body><br /></html>
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