求该结果的preg_replace的轮换写法

求该结果的preg_replace的替换写法
$url=http://www.xxx.com/66/
preg_replace("#^\/(\d{2,4})\/?$#","name/index.php?t=1&id=$1",strtolower($url));
通过以上我能得到一个重写的网址：name/index.php?t=1&sid=66 

我如何能直接通过一次正则替换，替换出一个数组：如下？
array(
      'name'=>index.php,
      'param'=>array('t'=>1,'id'=66)
     );

------解决方案--------------------
一步不行，需要自行分析形成数组。
------解决方案--------------------

$url = 'http://www.xxx.com/66/';<br />
@preg_replace("#/(\d{2,4})/?$#e","\$t=array('name'=>'index.php','param'=>array('t'=>1,'id'=>$1))",strtolower($url));<br />
print_r($t);<br />

66Array
(
[name] => index.php
[param] => Array
(
[t] => 1
[id] => 66
)

)

------解决方案--------------------

$url='http://www.xxx.com/66/';<br />
$s= preg_replace("#\/(\d{2,4})\/?$#","/name/index.php?t=1&id=$1",strtolower($url));<br />
$ar=parse_url($s);<br />
$arr['name']=substr($ar['path'],strrpos($ar['path'],'/')+1);<br />
parse_str($ar['query'],$t);<br />
$arr['param']=$t;<br />
print_r($arr);