请教php解析url的内容

请教各位，我有一个URL ： http://help.ea.com/en/server-status/fifa-2016/  
请教我如何把内容里 PC Game Servers ，Playstation 3 ，XBOX 360，XBOX One，Playstation 4这些属性下的UPDATED解析到？然后用PHP页面显示出来？

回复讨论(解决方案)

//$html 就是获取的页面 html$s = simplexml_load_string($html);foreach($s->ul[0] as $li){	echo $li->h6[0].' - '.$li->p[0].'<br>';}/*PC Game Servers - Updated: 9:51 PM CST May, 15 Playstation 3 - Updated: 9:51 PM CST May, 15 XBOX 360 - Updated: 9:51 PM CST May, 15 XBOX One - Updated: 9:51 PM CST May, 15 Playstation 4 - Updated: 9:51 PM CST May, 15 */

//$html 就是获取的页面 html$s = simplexml_load_string($html);foreach($s->ul[0] as $li){	echo $li->h6[0].' - '.$li->p[0].'<br>';}/*PC Game Servers - Updated: 9:51 PM CST May, 15 Playstation 3 - Updated: 9:51 PM CST May, 15 XBOX 360 - Updated: 9:51 PM CST May, 15 XBOX One - Updated: 9:51 PM CST May, 15 Playstation 4 - Updated: 9:51 PM CST May, 15 */

能否给段完整的代码？我刚学PHP, 获取HTML内容没搞定我

//$html 就是获取的页面 html$s = simplexml_load_string($html);foreach($s->ul[0] as $li){	echo $li->h6[0].' - '.$li->p[0].'<br>';}/*PC Game Servers - Updated: 9:51 PM CST May, 15 Playstation 3 - Updated: 9:51 PM CST May, 15 XBOX 360 - Updated: 9:51 PM CST May, 15 XBOX One - Updated: 9:51 PM CST May, 15 Playstation 4 - Updated: 9:51 PM CST May, 15 */

能否给段完整的代码？我刚学PHP, 获取HTML内容没搞定我

$html= file_get_contents($url);

网站做了限制，你要打开这个网页查看它的cookie，并复制出来放在 $strCookie 中，我的cookie串就是下面 $strCookie的内容，改成你的就可以了

$strCookie = 'oauth_redirect=/en/server-status/fifa-2016/; PHPSESSID=nuqjjqj9aagnc8j2mglf82dj45; AWSELB=A32F41DF08C4BE7B7084C2525E0A6EA0DB38F970292F10DAB9FBCCA7735A84837B2C3A00FA5C83230EF9357A7A9E719B7CF0224072C74548F89DB34FEF6BDDBD0F640DAA52E77AC24ADCBD1AEEB365AA2D9CA5CA37';$url = 'http://help.ea.com/en/server-status/fifa-2016/';$html = mcurl($url,$strCookie); //紧接上面的代码//$s = simplexml_load_string($html);.....function mcurl($url,$strCookie) {    $ch = curl_init();    curl_setopt($ch, CURLOPT_URL, $url);	curl_setopt($ch, CURLOPT_COOKIE, $strCookie);    $data = curl_exec($ch);    curl_close($ch);    return $data;}