PHP如何通过URL访问，获得新的URL 【调用百度地图】-PHP 튜토리얼-php.cn

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PHP如何通过URL访问，获得新的URL 【调用百度地图】

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Jun 23, 2016 pm 01:55 PM

php url 지도 입장 부르다

我是想在手机微信上进行一段导航
当前导航的URL地址如果录入到IE地址栏中是能正常访问的：http://api.map.baidu.com/direction?origin=latlng:24.481428,118.124813|name:测试起点&destination=latlng:24.503361,118.139877|name:测试终点&mode=driving®ion=厦门&output=html

录入后，回车会发现地址变成了：
http://map.baidu.com/?l=&s=nav%26sn%3D1%24%24%24%2413149737.11%2C2794316.21%24%24%E6%B5%8B%E8%AF%95%E8%B5%B7%E7%82%B9%24%24%24%24%24%24%26en%3D1%24%24%24%2413151414.05%2C2796984.18%24%24%E6%B5%8B%E8%AF%95%E7%BB%88%E7%82%B9%24%24%24%24%24%24%26sc%3D194%26ec%3D194

想知道如果用PHP如何实现根据原来的URL，请求后得到新的URL？谢谢。

回复讨论(解决方案)

转码的原因是上面带中文的，我发现微信里,IPHONE导航页面打不开，是空白的。
但是如果通过URL请求后，得到的新URL，配置在微信里是可以正常打开百度地图的。

所以我想写一个函数来处理这个，求教高手，谢谢。

原?的url是http://api.map.baidu.com/direction?origin=latlng:24.481428,118.124813|name:测试起点&destination=latlng:24.503361,118.139877|name:测试终点&mode=driving®ion=厦门&output=html

新的url是http://map.baidu.com/?l=&s=nav%26sn%3D1%24%24%24%2413149737.11%2C2794316.21%24%24%E6%B5%8B%E8%AF%95%E8%B5%B7%E7%82%B9%24%24%24%24%24%24%26en%3D1%24%24%24%2413151414.05%2C2796984.18%24%24%E6%B5%8B%E8%AF%95%E7%BB%88%E7%82%B9%24%24%24%24%24%24%26sc%3D194%26ec%3D194

用新的url就可以打?了，?的不行，??？

所以你想可以根??url?取新url然後使用？

兄弟，是这个意思。我就像用旧的URL产生新的URL。
多谢啊。

<?php$url = 'http://api.map.baidu.com/direction?origin=latlng:24.481428,118.124813|name:测试起点&destination=latlng:24.503361,118.139877|name:测试终点&mode=driving&region=厦门&output=html';$newurl = getMapUrl($url);echo $newurl;function getMapUrl($url){    $result = get_headers($url, true);    return isset($result['Location'])? $result['Location'] : '';}?>

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<?php$url = 'http://api.map.baidu.com/direction?origin=latlng:24.481428,118.124813|name:测试起点&destination=latlng:24.503361,118.139877|name:测试终点&mode=driving&region=厦门&output=html';$newurl = getMapUrl($url);echo $newurl;function getMapUrl($url){    $result = get_headers($url, true);    return isset($result['Location'])? $result['Location'] : '';}?>

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兄弟，感谢回复。
不过我用的是新浪SAE,里面提示我：
Warning: get_headers() has been disabled for security reasons in test.php on line 7

get_headers() 还能有别的办法替换么？谢谢。

试试.

$url = 'http://api.map.baidu.com/direction?origin=latlng:24.481428,118.124813|name:测试起点&destination=latlng:24.503361,118.139877|name:测试终点&mode=driving&region=厦门&output=html';$newurl = getMapUrl($url);echo $newurl;function getMapUrl($url){    file_get_contents($url);    $result = $http_response_header;    if($result){        foreach($result as $val){            if(substr($val,0,10)=='Location: '){                return str_replace('Location: ','', $val);            }        }    }    return '';}

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禁用的函数:

php_real_logo_guid
php_egg_logo_guid
readlink
linkinfo
symlink
link
set_file_buffer
exec
system
escapeshellcmd
escapeshellarg
passthru
shell_exec
proc_open
proc_close
proc_terminate
proc_get_status
proc_nice
getmyuid
getmygid
getmyinode
putenv
getopt
sys_getloadavg
getrusage
get_current_user
magic_quotes_runtime
set_magic_quotes_runtime
import_request_variables
debug_zval_dump
ini_alter
dl
pclose
popen
stream_socket_client
stream_socket_server
stream_socket_accept
stream_socket_pair
stream_get_transports
stream_wrapper_restore
get_headers
mail
mb_send_mail
openlog
syslog
closelog
apc_add
apc_bin_dump
apc_bin_dumpfile
apc_bin_load
apc_bin_loadfile
apc_cache_info
apc_cas
apc_clear_cache
apc_compile_file
apc_dec
apc_define_constants
apc_delete_file
apc_delete
apc_exists
apc_fetch
apc_inc
apc_load_constants
apc_sma_info
apc_store
flock
pfsockopen
posix_kill
apache_child_terminate
apache_get_modules
apache_get_version
apache_getenv
apache_lookup_uri
apache_reset_timeout
apache_response_headers
apache_setenv
virtual
mysql_pconnect
socket_create
socket_create_pair
禁用的类:

SQLiteDatabase
SQLiteResult
SQLiteUnbuffered
SQLiteException
APCIterator

urlencode?

试试.

$url = 'http://api.map.baidu.com/direction?origin=latlng:24.481428,118.124813|name:测试起点&destination=latlng:24.503361,118.139877|name:测试终点&mode=driving&region=厦门&output=html';$newurl = getMapUrl($url);echo $newurl;function getMapUrl($url){    file_get_contents($url);    $result = $http_response_header;    if($result){        foreach($result as $val){            if(substr($val,0,10)=='Location: '){                return str_replace('Location: ','', $val);            }        }    }    return '';}

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兄弟，给力啊。100分都给你了。结贴，哈。
谢谢。

看的晚了，还找了一个，顺便分享。

private function getHeadersNew($url){ $ch= curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_NOBODY, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_HEADER, 1); $f=curl_exec($ch); curl_close($ch); $h=explode("\n",$f); $r=array(); foreach( $h as $t){   $rr=explode(":",$t,2);   if(count($rr)==2 ){ $r[$rr[0]]=trim($rr[1]);} } return $r; }

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